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Angelina_Jolie [31]
3 years ago
12

C. You push a sled of mass 15 kg across the snow with a force of 180 N for a distance of 2.5 m. There is no friction. If the sle

d started at rest, what is the velocity
of the sled after you push it? Please I really need help 60 pointsss
Physics
1 answer:
Svetllana [295]3 years ago
4 0

Explanation:

7.7 m/s

1st determine you subject slade to you have a mass of 15 kg being subjected to a force of 180N

so.

180N/15kg=180(kg m)/s^2/15kg=12 ms^2

now determine how long u pushed it

d=0.5 A T^2

sutable the known values getting

2.5 m = 0.5 12 ms^2 T^2

2.5m= 0.6 ms^2 T^2

0.41667 s^2=T^2

0.645497224s=T

the velocity multiply the time by the acceleration giving

0.645497224 s 12 ms^2 =7.745966692 ms.

after rounding the 2 significant u get 7.7 ms

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A horizontal spring on a frictionless surface has a spring constant of 10 N/m with a mass of 2kg attached to the end of the spri
Alex

Answer:

0.356 times the mass pass through equilibrium per second.

Explanation:

Given that,

Spring constant = 10 N/m

Mass = 2 kg

Stretched spring = 2m

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Using formula of frequency

f=\dfrac{1}{2pi}\sqrt{\dfrac{k}{m}}

Where, m = mass

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Put the value into the formula

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4 0
3 years ago
An object is placed 18 cm in front of spherical mirror.if the image is formed at 4cm to the right of the mirror, calculate it's
ivolga24 [154]
1) Focal length

We can find the focal length of the mirror by using the mirror equation:
\frac{1}{f}= \frac{1}{d_o}+ \frac{1}{d_i} (1)
where 
f is the focal length
d_o is the distance of the object from the mirror
d_i is the distance of the image from the mirror

In this case, d_o = 18 cm, while d_i=-4 cm (the distance of the image should be taken as negative, because the image is to the right (behind) of the mirror, so it is virtual). If we use these data inside (1), we find the focal length of the mirror:
\frac{1}{f}= \frac{1}{18 cm}- \frac{1}{4 cm}=- \frac{7}{36 cm}
from which we find
f=- \frac{36}{7} cm=-5.1 cm

2) The mirror is convex: in fact, for the sign convention, a concave mirror has positive focal length while a convex mirror has negative focal length. In this case, the focal length is negative, so the mirror is convex.

3) The image is virtual, because it is behind the mirror and in fact we have taken its distance from the mirror as negative.

4) The radius of curvature of a mirror is twice its focal length, so for the mirror in our problem the radius of curvature is:
r=2f=2 \cdot 5.1 cm=10.2 cm
3 0
4 years ago
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