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Anastasy [175]
3 years ago
12

Which describes how a turbine works to produce energy for electricity? A. Energy from various energy sources, such as wind or fr

om burning fossil fuels, is used to spin the blades of the turbine. The turbine then powers a generator, which produces electricity. B. Energy from various energy sources, such as wind or from burning fossil fuels, is used to spin the blades of the turbine, which produces electricity. C. The turbine produces energy from various energy sources like wind or burning fossil fuels to drive the generator to make electricity. D. The generator produces energy from various energy sources like wind or burning fossil fuels to drive the turbine to make electricity.
Physics
1 answer:
OLEGan [10]3 years ago
5 0
The answer is A. Energy from <span>various energy sources, such as wind or from burning fossil fuels, is used to spin the blades of the turbine. The turbine then powers a generator, which produces electricity.

Works on simple principle of the turbine blades translation of energy sources causing the mechanical spin of the blades which is connected to a rotor which spins the main shaft of generator thus producing electricity.</span>
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An 80 kg astronaut has gone outside his space capsule to do some repair work. Unfortunately, he forgot to lock his safety tether
Anna [14]

Answer:

the time taken by the astronaut to reach safety = 9.8 hr

Explanation:

The equation for intensity can be written as :

I = \frac{P}{A}

where :

\frac{I}{c}= \frac{F}{A}

Replacing that into the above previous equation; we have:

\frac{P}{Ac}=\frac{F}{A}

F = \frac{P}{c}

However ; the force needed to push the astronaut is as follows:

F = ma

where ;

m = mass of the  astronaut and a = its acceleration

we as well say;

\frac{P}{c} = ma

a = \frac{P}{mc}

Replacing P with 1000 W ; m with 80 kg and 3*10^{8} \  m/s for  c

Then; a = \frac{1000 \ W}{(80)(3.0*10^8)}

a = 4.2*10^{-8} \ m/s

It is also known that the battery will run for one hour and after which the battery on the laser will run out

Then to determine the change in the position after the first hour ; we have:

\Delta x_1 = \frac{1}{2}*4.2*10^{-8} \ m/s^2 ) (1.0 \ h)^2

\Delta x_1 = \frac{1}{2}*4.2*10^{-8} \ m/s^2 ) (1.0 *3600 s)^2

= 0.27 m

Furthermore, the final velocity of the astronaut is determined as:

v_1 = at_1

where ;

v_1 = final \ velocity

replacing t_1 = 1.0 \ h and a =  4.2*10^{-8} \ m/s; Then:

v_1 = (4.2*10^8 \ m/s * 1.0 \ h * \frac{ 3600\ s}{1.0 \ h})

v_1 =  1.51 *10^{-4} \ m/s

Also; when he drifted 5.0 m away from the capsule; the distance is far short of the 5 m but he still have 9 hours left of oxygen . In addition to that, he acceleration is also zero and the final velocity remains the same, so:

To find the final distance traveled by the astronaut ;we have:

\Delta x_2 = d - \Delta x_1

where;

\Delta x_2 = the final distance

d = total distance

So;

\Delta x_2 = 5 m - 0.27 m \\ \\ \Delta x_2 = 4.73 \ m

The time taken to reach the final distance can be calculated as:

t_2 = \frac{\Delta x_2 }{v_1}

where;

t_2 = is the  time to  reach the final distance

Replacing 4.73 for {\Delta x_2 } and  1.51*10^{-4} m/s for v_1

t_2 = \frac{4.73 \ m }{1.51*10^{-4} \ m/s}

t_2 = 31500 \ s (\frac{1.0 \ h}{3600 \ s} )

t_2 = 8.8 \ h

We knew the laser was operated for 1 hour; thus the total time taken by the astronaut to  reach the final distance is the sum of the time taken to reach the final distance and the operated time of the laser.

Hence ; the time taken by the astronaut to reach safety = 9.8 hr

8 0
3 years ago
The KE of a body becomes 2 times of its original value then the new momentum will be more than its initial momentum by​
sladkih [1.3K]

Answer:

√2

Explanation:

If the final kinetic energy is 2 times the initial kinetic energy:

KE = 2 KE₀

½ mv² = 2 (½ mv₀²)

v² = 2 v₀²

v = √2 v₀

Therefore, the ratio of the final momentum to the initial momentum is:

p / p₀

mv / (mv₀)

v / v₀

√2

7 0
3 years ago
I don’t how to woke this
NeX [460]
Use the calculator to find out the answer
3 0
4 years ago
A conventional current of 8 A runs clockwise in a circular loop of wire in the plane, with center at the origin and with radius
alisha [4.7K]

Answer:

I2 = 3.076 A

Explanation:

In order to calculate the current in the second loop, you take into account that the magnitude of the magnetic field at the center of the ring is given by the following formula:

B=\frac{\mu_oI}{2R}        (1)

I: current in the wire

R: radius of the wire

μo: magnetic permeability of vacuum = 4π*10^-7 T/A

In the case of the two wires with opposite currents and different radius, but in the same plane, you have that the magnitude of the magnetic field at the center of the rings is:

B_T=\frac{\mu_oI_1}{2R_1}-\frac{\mu_oI_2}{2R_2}         (2)

I1: current of the first ring = 8A

R1: radius of the first ring = 0.078m

I2: current of the second ring = ?

R2: radius of the first second = 0.03m

To find the values of the current of the second ring, which makes the magnitude of the magnetic field equal to zero, you solve the equation (2) for I2:

\frac{\mu_oI_2}{2R_2}=\frac{\mu_oI_1}{2R_1}\\\\I_2=I_1\frac{R_2}{R_1}=(8A)\frac{0.03m}{0.078m}=3.076A

The current of the second ring is 3.076A and makes that the magntiude of the total magnetic field generated for both rings is equal to zero.

5 0
3 years ago
Does the electrical conductivity of a wire affect the strength of an electromagnet?
Mkey [24]
The strength of the electromagnet depends directly on the
current (amps) in the wire that the coil is made out of. 
That current is going to be determined by the voltage of the
battery or power supply that powers the magnet, and by the
resistance of the wire.  So yes, the properties of the wire do
have a direct effect on the strength of the magnet.  If you
tried to make an electromagnet with a coil of wet spaghetti,
it would work, but you would need a humongous power supply
to get any significant strength out of the magnet.
4 0
3 years ago
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