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3 years ago

I need help again. Plzzzzz

Mathematics

1 answer:

strojnjashka [21]3 years ago

5 0

Answer:

x =4.58

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean theorem

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

x^2 + 10 ^2 = 11^2

x^2 +100 =121

x^2 = 121-100

x^2 =21

take the square root of each side

sqrt(x^2) = sqrt(21)

x =4.582575695

To the nearest hundredth

x =4.58

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A circle with a radius of 5 is inscribed in a equilateral triangle. What is the area of the triangle's area minus the circle's a

Aleonysh [2.5K]

First off, the area of the circle would be 78.54

Now, you would do (area of the triangle)--- AT-78.54=answer

I don't know how to find the area of the triangle with just the circle's radius, so this is all I can do. I'm sorry!

4 0

4 years ago

Janet has three times as many dimes as nickels and twice as many quarters as nickels. If she has $5.10 in all, how many nickels,

Mama L [17]

If number of nickel = n
number of dimes = 3n
number of quarters = 2n

Amount of nickel = 5n
Amount of dimes = 30n
Amount of quaters = 50n

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In short, Your Answer would be Option C

Hope this helps!

6 0

4 years ago

A coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces. A random sample of 15 co

Luda [366]

Answer:

We conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

Step-by-step explanation:

We are given that a coffee packaging plant claims that the mean weight of coffee in its containers is at least 32 ounces.

A random sample of 15 containers were weighed and the mean weight was 31.8 ounces with a sample standard deviation of 0.48 ounces.

Let $\mu$ = mean weight of coffee in its containers.

SO, Null Hypothesis, $H_0$ : $\mu \geq$ 32 ounces {means that the mean weight of coffee in its containers is at least 32 ounces}

Alternate Hypothesis, $H_A$ : $\mu$ < 32 ounces {means that the mean weight of coffee in its containers is less than 32 ounces}

The test statistics that would be used here One-sample t-test statistics as we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = 31.8 ounces

s = sample standard deviation = 0.48 ounces

n = sample of containers = 15

So, the test statistics = $\frac{31.8 -32}{\frac{0.48}{\sqrt{15} } }$ ~ $t_1_4$

= -1.614

The value of t test statistics is -1.614.

Now, at 0.01 significance level the t table gives critical value of -2.624 at 14 degree of freedom for left-tailed test.

Since our test statistic is more than the critical value of t as -1.614 > -2.624, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the mean weight of coffee in its containers is at least 32 ounces which means that the data support the claim.

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4 years ago

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tatyana61 [14]

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3 years ago

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Ne4ueva [31]

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4 years ago