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atroni [7]
3 years ago
11

Please help!! Which number is greater? a)The square root of 64 b) The square root of 16

Mathematics
2 answers:
miskamm [114]3 years ago
5 0

Answer:

Neither, they are both equal.

Step-by-step explanation:

FYI, that three in front of the radical in the first expression is actually <em>cube root.</em> The cube root of 64 is 4, and the square root of 16 is 4.

\sqrt[3]{64} =4\\\sqrt{16}=4\\4=4

svlad2 [7]3 years ago
5 0

\huge\text{Hey there!}

\huge\textsf{Option A }\huge\boxed {\downarrow}

\huge\boxed{\rm{\sqrt[3]{64}}}}\\\huge\boxed{= \rm{\sqrt[3]{4^3}}}}\\\huge\boxed{= \rm{\sqrt[3]{4\times4 \times4}}}\\\huge\boxed{\rm{\rightarrow \sqrt{64}= 8, \ because \ 8\times8 = \bf  64}}\\\huge\boxed{\rm{{= \dfrac{8}{2}\rightarrow 8\div 2 \rightarrow \bf 4}}}

\huge\boxed{\textsf{Option A.) answer: \bf 4}}

\huge\textsf{Possible Option A. part II }\huge\boxed\downarrow

\huge\boxed{\rm{\sqrt{64} = \sqrt{8\times8}= \bf 8}}\\\huge\boxed{\text{Possible answer for Option A.  part II: \bf 8}}

\huge\textsf{Option B }\huge\boxed\downarrow

\huge\boxed{\rm{\sqrt{16}}}\\\huge\boxed{\rm{= \sqrt{4\times4}}}\\\huge\boxed{\rm{= \sqrt{16} \rightarrow \bold{4}\rightarrow 4\times4 \rightarrow \bf 16}}

\huge\boxed{\textsf{Option B.) answer: \bf 4}}

\huge\boxed{{\textsf{Based on the given information \boxed{\textsf{\bf NEITHER}} is}}}\\\huge\boxed{\textsf{the answer because it seems reasonable \& both}}\\\huge\boxed{\textsf{choices are very much equivalent to each other}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

~\frak{Amphitrite1040:)}

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