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fgiga [73]
3 years ago
7

Jason has 34 blueberry scones and 85 raspberry scones. There is 17 bags of scones each filled with an equal amount of blueberry

scones and raspberry scones. How many blueberry scones and how many blackberry scones can go in each bag?
Mathematics
2 answers:
ozzi3 years ago
8 0

Answer:

2 blueberry and 5 raspberry scones go in each bag

Step-by-step explanation:

34+85=119

119/17=7

34/85= 2/5

so 2 blueberry and 5 raspberry scones go in each bag

hope that helps :)

Ksju [112]3 years ago
3 0

Answer:

2 Blueberry scones and 5 Raspberry scones

Step-by-step explanation:

Given:

34 Blueberry scones

85 raspberry scones

17 Bags to fit scones

34 Blueberry so 34 divided by the Bag 17 (34 ÷ 17 = 2)

85 Raspberry scones so 85 divided by the Bag 17 ( 84 ÷ 17 = 5)

Therefore Jason can put 2 Blueberry scones and 5 Raspberry scones in each Bag

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Match each quotient with its answer when expressed in the form of a + bi.
kykrilka [37]

There is a typo in the available options for this problem. BOTH options B and E are 3/25+4/25i. One of those options should be 3/25-4/25i. So check your problem carefully and be sure to select the correct answer.

1. D. 1 + 0i
2. A. -7/25 + 24/25i
3. B or E, 3/25 + 4/25i
4. F. 3-4i
5. B or E, 3/25 - 4/25i
6. C. -7/25 -24/25i

For this problem, you need to perform complex division, then select the matching answer from the available options. In order to perform a complex division, simply multiply the numerator and denominator by the conjugate of the denominator. The conjugate of the denominator is simply the denominator with the sign of the complex term inverted. So:
1. i/i
Let's rewrite as (0 + i)/(0 + i)
(0 + i)/(0+i) * (0 - i)/(0 - i) 
= (0*0 + 0*i - 0*i - i^2)/(0*0 + 0*i - 0*i - i^2)
= (0 - -1)/(0 - -1)
= 1/1
= 1 + 0i which is option "D"

2. 3+4i/3-4i
3+4i/3-4i * 3+4i/3+4i
= (9 + 12i + 12i + 16i^2) / (9 - 12i + 12i - 16i^2)
= (-7 + 24i) / 25
= -7/25 + 24/25i, which matches option "A"

3. 1/3-4i
1/3-4i * 3+4i/3+4i
= (3 + 4i)/(9 + 12i - 12i - 16i^2)
= (3 + 4i)/(9 - -16)
= (3 + 4i)/25

= 3/25 + 4/25i, which matches option "B" or "E". BE SURE TO SELECT THE
CORRECT OPTION. You want 3/24 PLUS 4/25i.

4. 3-4i/1 
3-4i/1 * 1/1 = 3-4i, which matches option "F"

5. 1/3+4i 
1/3+4i * 3-4i/3-4i
= 3-4i/(9 + 12i - 12i - 16i^2)
= 3-4i/25
= 3/25 - 4/25i, which matches option "B" or "E". BE SURE TO SELECT THE
CORRECT OPTION. You want 3/24 MINUS 4/25i.


6. 3-4i/3+4i
3-4i/3+4i * 3-4i/3-4i
= (9 - 12i - 12i + 16i^2) / (9 - 12i + 12i - 16i^2)
= (9 - 12i - 12i + -16) / (9 - 12i + 12i - -16)
= (-7 - 24i) / 25
= -7/25 -24/25i, which matches option "C"
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5+10x+5.15=60.15 what's the value of x?
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The value of x is 5
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The estimated average speed you found earlier in the lesson was 30 miles per hour. How does your estimated speed compare to the
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Divide the total distance traveled by the total time spent traveling. Your estimated speed should be reletively close to your calculated speed.

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In Exercises 9-14, decide whether enough information
Degger [83]

The triangles that can be proved to be congruent by the SAS Congruence Theorem are:

10. ΔLMN and ΔNQP

13. ΔEFH and ΔGHF

The triangles that cannot be proved to be congruent by the SAS Congruence Theorem due to insufficient information are:

9. ΔABD and ΔCDB

12. ΔQRV and ΔTSU

14. ΔKLM and ΔMNK

11. ΔYXZ and ΔWXZ

<h3>What is the SAS Congruence Theorem?</h3>
  • If two triangles have two pairs of corresponding sides that are congruent, and a pair of corresponding included angle that are congruent, both triangles can be proven to be congruent triangles by the SAS Congruence Theorem.

Thus:

9. ΔABD and ΔCDB have:

  • one pair of congruent <em>non-included angles </em>- ∠ABD ≅ ∠CDB
  • two pairs of congruent sides - AD ≅ BC, and BD ≅ BD

ΔABD and ΔCDB lack a pair of <em>included angles</em>, therefore, the information given is not enough to prove the triangles are congruent by the SAS Congruence Theorem.

10. ΔLMN and ΔNQP have:

  • one pair of congruent <em>included angles </em>- ∠LMN ≅ ∠NQP
  • two pairs of congruent sides - LM ≅ NQ, and MN ≅ QP

ΔLMN and ΔNQP, therefore, have enough information to prove that they are congruent triangles by the SAS Congruence Theorem.

11. ΔYXZ and ΔWXZ have:

  • one pair of congruent <em>non-included angles </em>- ∠YXZ ≅ ∠WXZ
  • two pairs of congruent sides - XZ ≅ XZ, and XW ≅ YZ

ΔYXZ and ΔWXZ lack a pair of <em>included angles</em>, therefore, the information given is not enough to prove the triangles are congruent by the SAS Congruence Theorem.

12. ΔQRV and ΔTSU do not have enough information to prove they are congruent by the SAS Congruence Theorem.

13. ΔEFH and ΔGHF have two pairs of congruent sides and a pair of congruent <em>included angles</em><em>, </em>therefore, there is enough information to prove they are congruent by the SAS Congruence Theorem.

14. ΔKLM and ΔMNK do not have enough information to prove they are congruent by the SAS Congruence Theorem.

Therefore, the triangles that can be proved to be congruent by the SAS Congruence Theorem are:

10. ΔLMN and ΔNQP

13. ΔEFH and ΔGHF

The triangles that cannot be proved to be congruent by the SAS Congruence Theorem due to insufficient information are:

9. ΔABD and ΔCDB

12. ΔQRV and ΔTSU

14. ΔKLM and ΔMNK

11. ΔYXZ and ΔWXZ

Learn more about SAS Congruence Theorem on:

brainly.com/question/13408604

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So how can I use compatible numbers to estimate the total cost of the field trip.
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By being able to pair the same things it wills simplify the question adding brackets will hwlp
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