A microprocessor can directly process machine code but most programmers almost never write in it.
C. Machine code
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Answer:
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The INPUT code of the given programme in Java would be as given below:
In this first we are taking input of two integers j and k from the user and then performing the required operations over it
import java.util.
Scanner; public class LabProgram {
public static void main(String[ ] args) {
Scanner scnr = new Scanner(System.in);
int i,j;
i = scnr.nextInt();
j = scnr.nextInt();
if(i<=j) {
int k = i;
while (k <= j) {
System.out.print(k + " ");
k = k + 5;
}
System.out.println();
}
else{
System.out.println("Second integer can't be less than first.");
}
}
}
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Answer:
Here it is
Explanation:
#include <iostream>
using namespace std;
int main()
{
int a, b;
cin >> a >> b;
int nr_digits1 = 0, nr_digits2 = 0;
int sum1 = 0, sum2 = 0;
int max_digit1 = 0, max_digit2 = 0;
while (a > 1)
{
int digit = a % 10;
nr_digits1 += 1;
sum1 += digit;
if (digit > max_digit1)
{
max_digit1 = digit;
}
a /= 10;
}
while (b > 1)
{
int digit = b % 10;
nr_digits2 += 1;
sum2 += digit;
if (digit > max_digit2)
{
max_digit2 = digit;
}
b /= 10;
}
cout << "For a: \n" << " No. of digits: " << nr_digits1 << "\n";
cout << " Sum of digits: " << sum1 << "\n";
cout << " Max digit: " << max_digit1 << "\n";
cout << "\n";
cout << "For b: \n" << " No. of digits: " << nr_digits2 << "\n";
cout << " Sum of digits: " << sum2 << "\n";
cout << " Max digit: " << max_digit2 << "\n";
return 0;
}
