The probability that a student participates in both sports and music is 108/1376
<u>Explanation:</u>
Let x be the number of students participating in both sports and music
According to the question:
P(A or B) = P(A) + P(B) - P(A and B)
P(sports or music) = P(sports) + P(music) - P(sports and music)
![\frac{974}{1376} = \frac{649}{1376} + \frac{433}{1376} - \frac{x}{1376} \\\\974 = 1082 - x\\\\x = 108](https://tex.z-dn.net/?f=%5Cfrac%7B974%7D%7B1376%7D%20%3D%20%5Cfrac%7B649%7D%7B1376%7D%20%2B%20%5Cfrac%7B433%7D%7B1376%7D%20-%20%5Cfrac%7Bx%7D%7B1376%7D%20%5C%5C%5C%5C974%20%3D%201082%20-%20x%5C%5C%5C%5Cx%20%3D%20108)
P(sports and music) = ![\frac{108}{1376}](https://tex.z-dn.net/?f=%5Cfrac%7B108%7D%7B1376%7D)
Therefore, the probability that a student participates in both sports and music is 108/1376
Answer:
2 sqrt(15)
Step-by-step explanation:
Using the secant tangent formula
(whole secant) x (external part) = (tangent)^2
(5+7) * 5 = x^2
12*5 = x^2
60 = x^2
Taking the square root
sqrt(60) = sqrt(x^2)
sqrt(4*15) = x
2 sqrt(15) =x
We have the following expression:
log8 (3 ^ root (1/64))
Rewriting the expression we have:
log8 (1/4)
The equivalent expression for logarithm properties is:
log8 (1/4) = - 2/3
Answer:
The answer for this case is given by:
-2/3
option C
Answer:
its c plse mark me brainliest
Step-by-step explanation: