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MAVERICK [17]
3 years ago
12

What set of transformations could be applied to rectangle ABCD to create A″B″C″D″? 'Rectangle formed by ordered pairs A at negat

ive 4, 2, B at negative 4, 1, C at negative 1, 1, D at negative 1, 2. Second rectangle formed by ordered pairs A double prime at 2, negative 4, B double prime 1, negative 4, C double prime at 1, negative 1, D double prime at 2, negative 1. Reflected over the x‒axis and rotated 180° Reflected over the y-axis and rotated 180° Reflected over the x‒axis and rotated 90° counterclockwise Reflected over the y-axis and rotated 90° counterclockwise
Mathematics
1 answer:
tigry1 [53]3 years ago
3 0

Answer:

wag kana mag aral lol

Step-by-step explanation:

sungin mo module mo

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Janet invested $10,000, part at 2% and part at 12%. if the total interest at the end of the year is $600, how much did she inves
Ivan

Janet invested $6000 at 2 %.

Let <em>x</em> = amount invested at 2 %. Then 10 000 - <em>x</em> = amount invested at 12 %

interest at 2 % + interest at 12 % = 600

0.02<em>x</em> + 0.12(10 000 –<em> x</em>) = 600

0.02<em>x</em> + 1200 – 0.12<em>x</em> = 600

0.10<em>x</em> = 600

x = 600/0.10 = 6000

3 0
3 years ago
How many people scored below 80?<br><br><br><br> 21<br> 18<br> 11<br> 12
Airida [17]
The answer would be 11
7 0
3 years ago
The diameter of a circular plate is 12 inches. What is the area of the plate? Round your answer to the nearest tenth of a square
Kay [80]

Answer:

Plate Area = PI * radius^2

Plate Area = 3.14159 * 6 * 6

Plate Area = 113.09724  square inches

Plate Area = 113.1 square inches (rounded)

Step-by-step explanation:

7 0
3 years ago
How do you write 13 hundreds 7 tens 9 ones 5 tenths 2 hundredth?
k0ka [10]
Cara desculpe se a resposta tiver errada mais eu acho que é 1379,52. foi onde cheguei com os cálculos mentais.
3 0
3 years ago
Read 2 more answers
Find the equation of the parabola that passes through the points
Darya [45]

Answer:

1.  The equation of parabola is y=x^2-6x+5.

2. The equation of parabola is y=-2x^2+8x-8.

Step-by-step explanation:

1.

Let the equation of parabola be

y=ax^2+bx+c

It is given that the parabola passing through points (0,5), (2,-3) and (-1,12).

5=a(0)^2+b(0)+c

5=c

The value of c is 5.

y=ax^2+bx+5

The equation must be satisfied by the points (2,-3) and (-1,12).

-3=a(2)^2+b(2)+5

-8=4a+2b

Divide both sides by 2.

-4=2a+b                         .... (1)

12=a(-1)^2+b(-1)+5

7=a-b                            .... (2)

From (1) and (2), we get

a=1,b=-6

Therefore equation of parabola is y=x^2-6x+5.

2.

Let the equation of parabola be

y=ax^2+bx+c

It is given that the parabola passing through points (2,0), (3,-2) and (1,-2).

0=a(2)^2+b(2)+c

0=4a+2b+c                      .... (3)

The equation must be satisfied by the points (3,-2) and (1,-2).

-2=a(3)^2+b(3)+c  

-2=9a+3b+c                     .... (4)

-2=a(1)^2+b(1)+c

-2=a+b+c                            .... (5)

On solving (1), (2) and (3), we get

a=-2,b=8,c=-8

Therefore equation of parabola is y=-2x^2+8x-8.

7 0
3 years ago
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