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sleet_krkn [62]
3 years ago
9

Help me out asap pls! For 20 points..

Mathematics
1 answer:
Sunny_sXe [5.5K]3 years ago
7 0
The answer is b. 9pi because 3^2xpi=9pi.
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The point A = (7,4) is dilated from the origin by a scale factor r = 3. What are the coordinates of A' ?
fomenos

Given:

The coordinates of point A are (7,4).

It is dilated from the origin by a scale factor r = 3.

To find:

The coordinates of A'.

Solution:

If a figure is dilated from the origin by a scale factor k, then

(x,y)\to (kx,ky)

Here, the figure is dilated from the origin by a scale factor 3, so the rule of dilation is given by:

(x,y)\to (3x,3y)

Using this rule, we get

A(7,4)\to A'(3(7),3(4))

A(7,4)\to A'(21,12)

Therefore, the coordinates of point A' are (21,12).

6 0
3 years ago
Help me and I’ll give you brainliest
kirill115 [55]

Answer:

50m

Step-by-step explanation:

The triangles are similar, so their sides are in ratio:

BC/BE=AD/ED

j/46=25/23

j=(25/23)(46)=50

6 0
2 years ago
87 1/2% of what number is 105?
vampirchik [111]

Answer:

120

Step-by-step explanation:

87.5% of what number is 105?

87.5%=0.875

105/0.875=120

3 0
3 years ago
X2 + 8x + 6
Svetradugi [14.3K]
You could put the ‘+6’ at the start of the equation so it would read as +6(x2+8x) and then expand the bracket as you normally would so you would get x2x6 which would get you 12x and then 6x8x which would get you 48x and then you could group both numbers together as they’re like terms and your final answer would be 60x
6 0
3 years ago
Using addition formula solve tan 15​
salantis [7]

Answer:

2 - \sqrt{3}

Step-by-step explanation:

Using the addition formula for tangent

tan(A - B) = \frac{tanA-tanB}{1+tanAtanB} and the exact values

tan45° = 1 , tan60° = \sqrt{3} , then

tan15° = tan(60 - 45)°

tan(60 - 45)°

= \frac{tan60-tan45}{1+tan60tan45}

= \frac{\sqrt{3}-1 }{1+\sqrt{3} }

Rationalise the denominator by multiplying numerator/ denominator by the conjugate of the denominator.

The conjugate of 1 + \sqrt{3} is 1 - \sqrt{3}

= \frac{(\sqrt{3}-1)(1-\sqrt{3})  }{(1+\sqrt{3})(1-\sqrt{3})  } ← expand numerator/denominator using FOIL

= \frac{\sqrt{3}-3-1+\sqrt{3}  }{1-3}

= \frac{-4+2\sqrt{3} }{-2}

= \frac{-4}{-2} + \frac{2\sqrt{3} }{-2}

= 2 - \sqrt{3}

3 0
3 years ago
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