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erik [133]
3 years ago
11

Given two angles that measure 50 degrees and 80 degrees and side that measures 4 feet, how many triangles, if any, can be constr

ucted?
Mathematics
1 answer:
kirza4 [7]3 years ago
3 0
The angles are the only constraint here that counts.  If one of the three interior angles of a supposed triangle is 50 degrees and another is 80 degrees, then the third angle must be 50 degrees.  Thus, we have a 50-50-80 triangle, which is isosceles though not a right triangle.  If 4 feet is a measure of one of the equal sides of a supposed triangle, then obviously the adjacent side also has measure 4 ft.

The set of angles remains the same (50-50-80), but subject to the constraint mentioned above, the measure of any one of the sides has infinitely many possible values, so long as those values are positive.

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Answer:

Cristal is correct because 7 x 600 is less than 6 x 7,000.

Step-by-step explanation:

Because they are just switching the numbers 7 and 6 and 7 x 6 = 6 x 7, you have to look at the number of zeros. As you can see, 7,000 has 1 more zero than 600, so Cristal is correct. Just like I said 7 x 6 and 6 x 7 is interchangeable, so is 7 x 600 and 6 x 700, they both equal 4,200. However, 6 x 7,000 is 42,000.

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