Question

Solve: [3(1/5)] + 75% - [1(3/10)]​

Answer 1

Step-by-step explanation:

$\large{\underline{\underline{\bf{\purple{Solution\: : - }}}}}$

$\begin{gathered}\\ \dashrightarrow{\sf{3\dfrac{1}{5}} + 75\% - {1\dfrac{3}{10}}} \\ \end{gathered}$

$\red \divideontimes$ Firstly, converting mixed fractions into improper fraction.

$\begin{gathered} \\ {\dashrightarrow{\sf{\dfrac{(3 \times 5) + 1}{5}} + 75\% - {\dfrac{(1 \times 10) + 3}{10}}}} \\ \end{gathered}$

$\begin{gathered}{\dashrightarrow{\sf{\dfrac{15 + 1}{5}} + 75\% - {\dfrac{10 + 3}{10}}}} \\ \end{gathered}$

$\begin{gathered}{\dashrightarrow{\sf{\dfrac{16}{5}} + 75\% - {\dfrac{13}{10}}}} \\ \end{gathered}$

$\red \divideontimes$ As we know that, 1% = 1/100, then converting 75% into improper fraction.

$\begin{gathered}\\{\dashrightarrow{\sf{\dfrac{16}{5}} + \dfrac{75}{100} - {\dfrac{13}{10}}}} \\ \end{gathered}$

$\red \divideontimes$ According to the BODMAS, Firstly we will perform the addition.

$\begin{gathered}\\{\dashrightarrow{\sf{\bigg(\dfrac{16}{5}} + \dfrac{75}{100} \bigg) - {\dfrac{13}{10}}}} \\ \end{gathered}$

$\red \divideontimes$ Taking the LCM of denominators.

$\begin{gathered}\\{\dashrightarrow{\sf{\bigg(\dfrac{(16 \times 20) + (75 \times 1)}{100}} \bigg) - {\dfrac{13}{10}}}} \\ \end{gathered}$

$\begin{gathered}{\dashrightarrow{\sf{\bigg(\dfrac{320 + 75 }{100}} \bigg) - {\dfrac{13}{10}}}} \\ \end{gathered}$

$\begin{gathered}{\dashrightarrow{\sf{\bigg(\dfrac{395 }{100}} \bigg) - {\dfrac{13}{10}}}} \\ \end{gathered}$

$\red \divideontimes$ Now, converting 395/100 in simplest form.

$\begin{gathered}\\ {\dashrightarrow{\sf{\bigg( \cancel{\dfrac{395 }{100}}} \bigg) - {\dfrac{13}{10}}}} \\ \end{gathered}$

$\begin{gathered}{\dashrightarrow{\sf{\bigg(\dfrac{79}{20}} \bigg) - {\dfrac{13}{10}}}} \\ \end{gathered}$

$\red \divideontimes$ Now, performing subtraction, according to BODMAS.

$\begin{gathered}\\ {\dashrightarrow{\sf{\dfrac{79}{20}} - {\dfrac{13}{10}}}} \\ \end{gathered}$

$\red \divideontimes$ Again, taking LCM of denominators.

$\begin{gathered}\\ {\dashrightarrow{\sf{\dfrac{(79 \times 1) - (13 \times 2)}{20}}}} \\ \end{gathered}$

$\begin{gathered}{\dashrightarrow{\sf{\dfrac{79 -26}{20}}}} \\ \end{gathered}$

$\begin{gathered}{\dashrightarrow{\sf{\dfrac{53}{20}}}} \\ \end{gathered}$

$\begin{gathered}\red{\bigstar{\underline{\boxed{\bf{Answer = \dfrac{53}{20}}}}}}\end{gathered}$

∴ The answer is 53/20.

$\begin{gathered}\end{gathered}$

Answer 2

Answer:

$2 \frac{13}{20}$

Step-by-step explanation:

$3 \frac{1}{5} + 75\% - 1 \frac{3}{10} \\ \frac{16}{5} + \frac{75}{100} - \frac{13}{10} \\ \frac{16}{5} + \frac{3}{4} - \frac{13}{10} \\ \frac{16 \times 4}{5 \times 4} + \frac{3 \times 5}{4 \times 5} - \frac{13 \times 2}{10 \times 2} \\ \frac{64 + 15 - 26}{20} \\ \frac{53}{20} \\ 2 \frac{13}{20}$