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3 years ago

Determine the slope of each line Plz help!!!

Mathematics

1 answer:

den301095 [7]3 years ago

7 0

Answer:

7/3

Step-by-step explanation:

To solve use: $m=\frac{y_{2} -y_{1} }{x_{2}-x_{1} }$

(-1,5) and (-7,-9)

x1 y1 x2 y2

m= $\frac{-9-5}{-7-(-1)}$ *When multiplying or dividing a negative by a negative you get a positive*

Solve:

m= $\frac{-14}{-6}$ or $\frac{-7}{-3}$ --------> $\frac{7}{3}$

Hope this helps!

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What are the rules for dividing signed numbers

Natali5045456 [20]

Alright, for the guide

basically,
when you divide 2 numbers with the same sign, the result is positive
example, $\frac{2}{4}=0.5$ and $\frac{-2}{-4}=0.5$

when you divide 2 numbers with different signs, the result is negative
example: $\frac{-2}{4}=-0.5$ and $\frac{2}{-4}=-0.5$

7 0

3 years ago

What is the MAD of 0,3,6,9,11,13,14

Romashka [77]

I believe if I did this correctly, it should be 4 2/7, hope this helps!

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3 years ago

Lucy correctly answered 70% of the questions on her science homework. She counted 14 correct answers. How many questions are the

Svet_ta [14]

Answer:

9.8

Step-by-step explanation:

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3 years ago

Use calculus to find the absolute maximum and minimum values of the function. (round all answers to three decimal places.) f(x)

Allisa [31]

Part A:

Given the function $f(x)=x+2\cos(x)$ , the absolute maximum or minimum occurs when $f'(x)=0$ .

$f'(x)=0 \\ \\ \Rightarrow1-2\sin{x}=0 \\ \\ \Rightarrow2\sin{x}=1 \\ \\ \Rightarrow\sin{x}= \frac{1}{2} \\ \\ \Rightarrow x=\sin^{-1}{\frac{1}{2}}= \frac{\pi}{6}$

Using the second derivative test,

$f''(x)=-2cosx \\ \\ \Rightarrow f''\left( \frac{\pi}{6} \right)=-2\cos{\left( \frac{\pi}{6} \right)}=-1.732$

Since the second derivative gives a negative number, the given function has a maximum point at $x=\frac{\pi}{6}$ .

And the maximum point is given by:

$f\left( \frac{\pi}{6} \right)=\frac{\pi}{6}+2\cos\left( \frac{\pi}{6} \right) \\ \\ =0.5236+2(0.8660)=0.5236+1.732 \\ \\ =\bold{2.256}$

i.e. $\left(\frac{\pi}{6},\ 2.256\right)$

Part B:

Given the function $f(x)=e^{-x}-e^{-2x}$ , the absolute maximum or minimum occurs when $f'(x)=0$ .

$f'(x)=0 \\ \\ \Rightarrow-e^{-x}+2e^{-2x}=0 \\ \\ \Rightarrow2e^{-2x}=e^{-x} \\ \\ \Rightarrow2e^{-x}=1 \\ \\ \Rightarrow e^{-x}=\frac{1}{2} \\ \\ \Rightarrow-x=\ln \frac{1}{2}=-0.6931 \\ \\ \Rightarrow x=0.6931$

Using the second derivative test,

$f''(x)=e^{-x}-4e^{-2x} \\ \\ \Rightarrow f''(0.6931)=e^{-0.6931}-4e^{-2(0.6931)} \\ \\ =0.5-4e^{-1.386}=0.5-4(0.25)=0.5-1 \\ \\ =-0.5$

Since the second derivative gives a negative number, the given function has a maximum point at $x=0.6931$ .

And the maximum point is given by:

$f(0.6931)=e^{-0.6931}-e^{-2(0.6931)} \\ \\ =0.5-e^{-1.386}=0.5-0.25=\bold{0.25}$

i.e. (0.693, 0.25)

3 0

3 years ago

Maggie's class bought three books at the book fair the book cost $15, $9 and $12. use parenthesis to write two different express

Vedmedyk [2.9K]

To determine the total class the whole class spent, you just have to simply add the individual costs of the three books. Using parenthesis, the solution can be written in the following two ways:

($15 + $9) + $12 = $36
$15 + ($9 + $12) = $36

No matter where you put the parenthesis, the final answer doesn't change. This is because of the Commutative Property of Addition. The order does not matter.

3 0

4 years ago