Answer:
The graph
has two zeros namely 3 and 1.
Step-by-step explanation:
Consider the given equation of graph
According to the Fundamental Theorem of Algebra
For a given polynomial of degree n can have a maximum of n roots.
Thus, for the given equation
the degree of polynomial is 2 , thus the function can have maximum of 2 roots.
We know at roots the value of function is 0 that is f(x) = 0,
Substitute f(x) = 0 , we get, ![f(x)=x^2-4x+3=0](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E2-4x%2B3%3D0)
This is a quadratic equation, ![x^2-4x+3=0](https://tex.z-dn.net/?f=x%5E2-4x%2B3%3D0)
We first solve it manually and then check by plotting graph.
Quadratic equation can be solved using middle term splitting method,
here, -4x can be written as -x-3x,
![x^2-4x+3=0 \Rightarrow x^2-x-3x+3=0](https://tex.z-dn.net/?f=x%5E2-4x%2B3%3D0%20%5CRightarrow%20x%5E2-x-3x%2B3%3D0)
![\Rightarrow x(x-1)-3(x-1)=0](https://tex.z-dn.net/?f=%5CRightarrow%20x%28x-1%29-3%28x-1%29%3D0)
![\Rightarrow (x-3)(x-1)=0](https://tex.z-dn.net/?f=%5CRightarrow%20%28x-3%29%28x-1%29%3D0)
Using zero product property, ![a\cdot b=0 \Rightarrow a=0\ or \ b=0](https://tex.z-dn.net/?f=a%5Ccdot%20b%3D0%20%5CRightarrow%20a%3D0%5C%20or%20%5C%20b%3D0)
or ![\Rightarrow (x-1)=0](https://tex.z-dn.net/?f=%5CRightarrow%20%28x-1%29%3D0)
or ![\Rightarrow x=1](https://tex.z-dn.net/?f=%5CRightarrow%20x%3D1)
Thus, the two zero of f(x) are 3 and 1.
We can also see on graph attached below that the graph
has two zeros namely 3 and 1.