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3 years ago

What is the answer to the digit 7 in 0.37 has a value_____ the value of the 7 in 0.73?

Mathematics

1 answer:

Inessa05 [86]3 years ago

6 0

What do you mean? 7 in 0.37 is 0.07 or 7 hundredths.
7 in 0.73 is 0.7 or 7 tenths?
Is that what you meant...

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2 years ago

6y+12=-2x x+3y=-6 In y form

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Answer:

both equations reduce to y = -1/3x -2

Step-by-step explanation:

In each case, subtract the term not containing y and divide by the coefficient of y.

1. 6y = -2x -12 . . . . 12 was subtracted from both sides

y = -1/3x -2 . . . . . . the equation was divided by 6

2. 3y = -x -6 . . . . . . x was subtracted from both sides

y = -1/3x -2 . . . . . the equation was divided by 3

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2 years ago

Let f(x)=x^2+3x−4 .

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3 years ago

Read 2 more answers

Given segments AB and CD intersect at E.

nata0808 [166]

The length of a segment is the distance between its endpoints.

$\mathbf{AB = 3\sqrt{2}}$
AB and CD are not congruent
AB does not bisect CD
CD does not bisect AB

(a) Length of AB

We have:

$\mathbf{A = (1,2)}$

$\mathbf{B = (4,5)}$

The length of AB is calculated using the following distance formula

$\mathbf{AB = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

So, we have:

$\mathbf{AB = \sqrt{(1 - 4)^2 + (2 - 5)^2}}$

$\mathbf{AB = \sqrt{18}}$

Simplify

$\mathbf{AB = 3\sqrt{2}}$

(b) Are AB and CD congruent

First, we calculate the length of CD using:

$\mathbf{CD = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}}$

Where:

$\mathbf{C = (2, 4)}$

$\mathbf{D = (2, 1)}$

So, we have:

$\mathbf{CD = \sqrt{(2 -2)^2 + (4 - 1)^2}}$

$\mathbf{CD = \sqrt{9}}$

$\mathbf{CD = 3}$

By comparison

$\mathbf{CD \ne AB}$

Hence, AB and CD are not congruent

(c) AB bisects CD or not?

If AB bisects CD, then:

$\mathbf{AB = \frac 12 \times CD}$

The above equation is not true, because:

$\mathbf{3\sqrt 2 \ne \frac 12 \times 3}$

Hence, AB does not bisect CD

(d) CD bisects AB or not?

If CD bisects AB, then:

$\mathbf{CD = \frac 12 \times AB}$

The above equation is not true, because:

$\mathbf{3 \ne \frac 12 \times 3\sqrt 2}$

Hence, CD does not bisect AB

Read more about lengths and bisections at:

brainly.com/question/20837270

7 0

2 years ago