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butalik [34]
3 years ago
13

Find the value of x and y.​

Mathematics
1 answer:
JulsSmile [24]3 years ago
6 0

Answer:

x = 14, y = 37.

Step-by-step explanation:

9x + 12 = 4y - 10      (exterior alternate angles are equal)

9x - 4y = -22 ..........A

The angle which is interiorly alternate to 3x is 180 - (9x + 12), so:

3x = 180 - (9x + 12)   (interior alternate angles are equal)

3x + 9x  = 168

12x = 168

x = 14

Substitute x = 14 into equation A:

9(14) - 4y = -22

4y = 9(14) + 22

4y = 148

y = 37.

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The net of a square pyramid is shown: What is the surface area of the figure? (A)0.7625 square inch
aniked [119]

Answer:

C. 0.6625 square inches

Step-by-step explanation:

To get the area of the net of a square pyramid;

We need to find the are of the square base and the area of the four triangles;

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6 0
4 years ago
A cone has a diameter of 10 inches. If its height is twice its radius, about what is the volume of the cone in cubic inches? Use
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Can someone help me out please, thank you.
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Here are a few rules about exponents you should know:

  1. Multiplying exponents of the same base: x^m*x^n=x^{m+n}
  2. Dividing exponents of the same base: \frac{x^m}{x^n}=x^{m-n}
  3. Powering a power to a power: (x^m)^n=x^{m*n}
  4. Converting a negative exponent into a positive one: x^{-m}=\frac{1}{x^m};\frac{1}{x^{-m}}=x^m

Firstly, multiply the y bases: \frac{z^5}{(-y^{-4}y^{-1}x^3)^{-3}}=\frac{z^5}{(-y^{-4+-1}x^3)^{-3}}=\frac{z^5}{(-y^{-5}x^3)^{-3}}

Next, solve the power: \frac{z^5}{(-y^{-5}x^3)^{-3}}=\frac{z^5}{-y^{-5*-3}x^{3*-3}}=\frac{z^5}{-y^{15}x^{-9}}

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