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Dimas [21]
2 years ago
15

Suppose I have an urn full of balls.10 balls are balck, 2 are blue,2 are red,1 is green. I reach into the urn and pull out a bal

l and record the colour. I then put it back in the urn. If i do this 10 times calculate
a) the probability I obtain exact 4 black balls
b) The probablility I obtain less than 2 red balls

For clarity we are putting the balls back into the urn after the colour is recorded.
Mathematics
1 answer:
Gelneren [198K]2 years ago
6 0

Answer:

Step-by-step explanation:

Assuming that each draw is independent of the last and that each ball is equally likely to be selected makes this a binomial distribution

a.) first find the probability of selecting a black ball, 2/10 or .2

{10\choose{4}}.2^4*.8^6=.08808384

b.) Probability of slecting a red ball: 1/10 or .1

Less than 2 is X=0 + X=1

{10\choose0}*.2^0*.8^{10}+{10\choose1}*.2*.8^9=.3758096384

i will leave you to do the rounding

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Answer:

( 3 , 7 )

Step-by-step explanation:

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A picture is 7 3/5 cm wide how much should it be trimmed to fit in a frame 7 3/10cm wide​
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I've done the y = equations but I don't know how to do this one.
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Consider the equation

-10x-y=-20

1) First row of the table

Set x=0 and solve as follows:

\begin{gathered} -10(0)-y=-20 \\ \Rightarrow-y=-20 \\ \Rightarrow y=20 \end{gathered}

The answer is y=20 and the pair x-y is (0,20)

2) Second row

Set x=1 and solve, as follows:

\begin{gathered} -10(1)-y=-20 \\ \Rightarrow-10-y=-20 \\ \Rightarrow-y=-10 \\ \Rightarrow y=10 \end{gathered}

The answers are y=10 and (1,10)

3) Third row.

Set y=0 and solve as follows:

\begin{gathered} -10x-(0)=-20 \\ \Rightarrow-10x=-20 \\ \Rightarrow x=\frac{20}{10}=2 \\ \Rightarrow x=2 \end{gathered}

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10 months ago
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Find the area of the region bounded by the line y=3x-6 and line y=-2x+8.
Vikentia [17]

Answer:

A = 12/5 units

Step-by-step explanation:

USING ALGEBRA:

We can find the intersection point between these two lines;

y = 3x - 6

y = -2x + 8

Set these two equations equal to each other.

3x - 6 = -2x + 8

Add 2x to both sides of the equation.

5x - 6 = 8

Add 6 to both sides of the equation.

5x = 14

Divide both sides of the equation by 5.

x = 14/5  

Find the y-value where these points intersect by plugging this x-value back into either equation.

y = 3(14/5) - 6

Multiply and simplify.

y = 42/5 - 6

Multiply 6 by (5/5) to get common denominators.

y = 42/5 - 30/5  

Subtract and simplify.

y = 12/5

These two lines intersect at the point 12/5. This is the height of the triangle formed by these two lines and the x-axis.

Now let's find the roots of these equations (where they touch the x-axis) so we can determine the base of the triangle.

Set both equations equal to 0.

(I) 0 = 3x - 6  

Add 6 both sides of the equation.

6 = 3x

Divide both sides of the equation by 3.

x = 2  

Set the second equation equal to 0.

(II) 0 = -2x + 8

Add 2x to both sides of the equation.

2x = 8

Divide both sides of the equation by 2.

x = 4

The base of the triangle is from (2,0) to (4,0), making it a length of 2 units.

The height of the triangle is 12/5 units.

Formula for the Area of a Triangle:

A = 1/2bh

Substitute 2 for b and 14/5 for h.

A = (1/2) · (2) · (12/5)

Multiply and simplify.

A = 12/5

The area of the region bounded by the lines y = 3x - 6 and y = -2x + 8 between the x-axis is 12/5 units.

3 0
2 years ago
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