(a) Given the position function
x(t) = (B m/s²) t² + 5 m
it's clear that the object accelerates at B m/s² (differentiate x(t) twice with respect to t), so that the force exerted on the object is
F(t) = (2 kg) (B m/s²) = 2B N
(b) Recall the work-energy theorem: the total work performed on an object is equal to the change in the object's kinetic energy. The object is displaced by
∆x = x(5 s) - x(0 s)
∆x = ((B m/s²) (5 s)² + 5 m) - ((B m/s²) (0 s)² + 5 m)
∆x = 25B m
Then the work W performed by F (provided there are no other forces acting in the direction of the object's motion) is
W = (2B N) (25B m) = 50B² J = 200 J
Solve for B :
50B² = 200
B² = 4
B = ± √4 = ± 2
Since the change in kinetic energy and hence work performed by F is positive, the sign of B must also be positive, so B = 2 and the object accelerates at 2 m/s².
(c) We found in part (b) that the object is displaced 25B m, and with B = 2 that comes out to ∆x = 50 m.
- If he has 18 vases, he can put 2 tulips in each
- If he has 12 vases, he can put 3 tulips in each
- If he has 9 vases, he can put 4 tulips in each
- If he has 6 vases, he can put 6 tulips in each
- If he has 4 vases, he can put 9 tulips in each
Answer:
Step-by-step explanation:
x 0 1 2 3 4 5 6 7
y 2 6 12 17 36 72 138 275
The points appear to follow an exponential growth curve.
The regression equation is
The figure below shows the graph of your points and the regression line.
Answer:
The second one
Step-by-step explanation:
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