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Drupady [299]
3 years ago
5

Miguel runs 5 miles in 38 minutes. At the same rate, how many miles would he run in 57 minutes?

Mathematics
2 answers:
cricket20 [7]3 years ago
8 0

Answer:

11.4 miles

Step-by-step explanation:

gavmur [86]3 years ago
3 0

7,5 miles

Step-by-step explanation:

5/x = 38/57

38x = 5 × 57

38x = 285

x = 285/38

x = 7,5 miles

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Nataly_w [17]

Answer:

the estimated answer is 10

Step-by-step explanation:

you have to round both numbers to the nearest ten and then subtract

3 0
3 years ago
A plane flies 1.2 hours at 120 mph on a bearing of
iogann1982 [59]

9514 1404 393

Answer:

  421.4 miles

Step-by-step explanation:

The flight legs are orthogonal, so the distance can be found using the Pythagorean theorem:

  1.2 h × 120 mph = 144 mi

  3.3 h × 120 mph = 396 mi

The distance at the end of the second flight leg is ...

  d = √(144² +396²) = √177552 ≈ 421.37

The plane is about 421.4 miles from its starting point.

_____

The heading to its end point is 20° +arctan(3.3/1.2) ≈ 90.02°.

4 0
3 years ago
Help its math ik u like math
choli [55]

Answer:

141.625

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
Rasheed bought two kinds of candy bars, chocolate and toffee, that came in packages of 2 bars each. He handed out 2/3 of the cho
Gnom [1K]

Answer:

Rasheed bought 3 packages of chocolate and 5 packages of toffee.

Step-by-step explanation:

In this case we have to found the number of bars that multiplied by the fractions presented give us an integer number and meets with the fact that the bars are an odd number because the packages came in packs of two bars.

For the case of the chocolate we have to find a number that meets this characteristics, we try with the number 6:

6*\frac{2}{3} =4

For chocolate Rasheed bought 3 packages, we can see that 6 bars meet the asked.

For the case of toffee, we try with number 10:

10*\frac{3}{5} =6

For toffee Rasheed bought 5 packages, we can see that 10 bars meet the asked.

Rasheed bought 3 packages of chocolate and 5 packages of toffee.

5 0
3 years ago
Use the diagram to solve for the three variables so that the quadrilateral will be a rhombus. Show all of your work for full cre
satela [25.4K]

Answer:

  • x = 4
  • y = 4
  • z = 7

Step-by-step explanation:

Each triangle is a right triangle, and all are congruent. So ...

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  90 -(4x +33) = (1/2)(12x +34)

  57 -4x = 6x +17 . . . . . . . eliminate parentheses

  40 = 10x . . . . . . . . . . . . .add 4x-17

  4 = x

We also have ...

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  6z +56 = 10z +28 . . . . . eliminate parentheses

  28 = 4z . . . . . . . . . . . . . .subtract 6z+28

  7 = z . . . . . . . . . . . . . . . . divide by 4

Since BC = CD ...

  x = y = 4

The values of the three variables are ...

  x = 4, y = 4, z = 7.

3 0
3 years ago
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