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4 years ago

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Which of the following inequalities matches the graph? graph of an inequality with a solid line through the points (1, 4) and (2

, 9) with shading below the line The correct inequality is not listed. 5x + y greater than or equal to 1 5x + y less than or equal to 1 5x − y greater than or equal to 1

2 answers:

gogolik [260]4 years ago

8 0

Answer with explanation:

Equation of line passing through the points (1, 4) and (2, 9) is given by

Formula

$\frac{y-y_{1}}{x-x_{1}}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\\text{Equation of line}\\\\\frac{y-4}{x-1}=\frac{9-4}{2-1}\\\\y-4=5(x-1)\\\\y-4=5x-5\\\\5x-y-5+4=0\\\\5x-y-1=0$

Now it is given that we have to shade below the line.

The most appropriate option among three is,

Option C:→5x − y greater than or equal to 1

Ganezh [65]4 years ago

6 0

Is 5x +y greater than or equal to 1

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The following chart shows a store's records of sales of stuffed toys for two months

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Answer:

None of the above answers

Step-by-step explanation:

Form a table as shown

Months Teddy Bears Rabbits Cats Horses Others Totals toys

September 225 275 245 260 199 1204

October 346 308 186 297 285 1422

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Cats decreased from 245 to 186

Others increased from 199 to 285,

285-199 = 86

percent increase was = increase/original quantity *100

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Total number of stuffed toys increased from 1204 to 1422

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After m months, the length of a fingernail is 10+3m millimeters. How long is the fingernail after eight months? 36 month?

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Step-by-step explanation:

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When the author visited Dublin, Ireland (home of Guinness Brewery employee William Gosset, who first developed the t distributio

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Answer:

The Decision Rule

Fail to reject the null hypothesis

The conclusion

There is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

Step-by-step explanation:

From the question we are told that

The data is

Car Ages 4 0 8 11 14 3 4 4 3 5 8 3 3 7 4 6 6 1 8 2 15 11 4 1 6 1 8

Taxi Ages 8 8 0 3 8 4 3 3 6 11 7 7 6 9 5 10 8 4 3 4

The level of significance $\alpha = 0.05$

Generally the null hypothesis is $H_o : \mu_1 - \mu_2 = 0$

the alternative hypothesis is $H_a : \mu_1 - \mu_2 > 0$

Generally the sample mean for the age of cars is mathematically represented as

$\= x_1 = \frac{\sum x_i }{n}$

=> $\= x_1 = \frac{4+ 0+ 8 +11 + \cdots + 8
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=> $\= x_1 = 5.56$

Generally the standard deviation of age of cars

$\sigma _1 = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }$

=> $\sigma _1 = \sqrt{\frac{(4 - 5.56)^2 + (0 - 5.56)^2+ (8 - 5.56)^2 + \cdots + 8}{ 27} }$

=> $\sigma _1 = 3.88$

Generally the sample mean for the age of taxi is mathematically represented as

$\= x_2 = \frac{\sum x_i }{n}$

=> $\= x_2 = \frac{8 +8 +0 + \cdots + 4
}{20}$

=> $\= x_2 = 5.85$

Generally the standard deviation of age of taxi

$\sigma _2 = \sqrt{\frac{\sum (x_i - \= x)^2}{n_1} }$

=> $\sigma _2 = \sqrt{\frac{(8 - 5.85)^2 + (8 - 5.85)^2+ (0 - 5.85)^2 + \cdots + 8}{ 20} }$

=> $\sigma _2 = 2.83$

Generally the test statistics is mathematically represented as

$t = \frac{(\= x_ 1 - \= x_2 ) - 0}{\sqrt{\frac{\sigma^2_1}{n_1} + \frac{\sigma^2_2}{n_2} } }$

=> $t = \frac{(5.56 - 5.85 ) - 0}{\sqrt{\frac{(3.88)^2}{27} + \frac{(2.83)}{20} }}$

=> $t = -0.30$

Generally the degree of freedom is mathematically represented as

$df = n_1 + n_2 -2$

$df = 27 + 20 -2$

$df = 45$

From the t distribution table the $P(t > t )$ at the obtained degree of freedom = 45 is

$P(t > -0.30 ) = 0.61722067$

So the p-value is

$p-value = P(t > T) = 0.61722067$

From the obtained values we see that the p-value > $\alpha$ hence we fail to reject the null hypothesis

Hence the there is no sufficient evidence to support the claim that the mean age of the cars is greater than that of taxi

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