9514 1404 393
Answer:
a) $2.40
b) $16.80
c) y = -2.40x +16.80
Step-by-step explanation:
a. Dylan's daily spending is the opposite of the slope of the line on the graph. That slope can be found using the slope formula:
m = (y2 -y1)/(x2 -x1)
m = (4.8 -12)/(5 -2) = -7.2/3 = -2.4
Dylan spends $2.40 at lunch every day.
__
b. The y-intercept can be found from the formula ...
b = y1 -m(x1)
b = 12 -(-2.40)(2) = 16.80
Dylan's dad gives him $16.80 at the beginning of each week.
__
c. The slope-intercept equation is ...
y = mx + b
y = -2.40x +16.80
Answer:
a). 85 people
b). 4362 people
Step-by-step explanation:
The given bar graph shows how many people per 100 spelled each word correctly.
a. From the graph given extreme end of the bar for the word "weird" is between 80 - 90.
Therefore, approximate number of the persons who spelled weird correctly will be <u>85</u> (rounded to the nearest 5).
b. The number of people who can correctly spelled word "weird" = 85
The number of people who can correctly spelled word "inoculate" = 35
In 100 people, number of people who can correctly spell "weird" more than "inoculate"
= 85 - 35
= 50
in a group of 8724 randomly selected people, number of people who can spell the word "weird" correctly more than "inoculate"
=
= <u>4362 </u>people
The answer is 240 please mark me as brainliest
The answer to this problem is $4.90
The plot that organizes the data into 4 groups of equal sizes is box and whisker plot.
The image below shows a box and whisker plot. Following are the elements of box and whisker plot:
Minimum = This is the smallest value of the data set
Q1 = First (Lower) Quartile of the data set. 25% of the data values lie below this point
Q2 = Second Quartile or Median. This is the central value so 50% of the data values lie below this point
Q3 = Third (Upper) Quartile of the data set. 75% of the data values lie below this point.
Maximum = This is the maximum value of the data set.
Based on box and whisker plot we can compare two or more sets of data by comparing the spread of the data. We can also directly observe from the box and whisker plot if the data is uniform, normal or skewed. Using box and whisker plot we can also visualize any outliers that may be in the data.