Answer:
A
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
Here (h, k) = (- 2, 3) and r = 3 , then
(x + 2)² + (y - 3)² = 9 ← expand left side using FOIL
x² + 4x + 4 + y² - 6y + 9 = 9 ( subtract 9 from both sides )
x² + y² + 4x - 6y + 4 = 0 → A
If you’re doing Kaleel to John (not the other way around), you could have 3:1, 3/1, or 3 to 1. Hope this helps!
Writing this word problem symbolically: 6x + 4 = x = 11.
Combining like terms, 5x = 7, and so x = 7/5 (answer)
9514 1404 393
Answer:
- -√5
- 3/5
- -4/5
Step-by-step explanation:
The relevant relations are ...
sec = ±√(tan² +1)
cos = 1/sec
csc = 1/sin = ±1/√(1 -cos²)
Sine and Cosecant are positive in quadrants I and II. Cosine and Secant are positive in quadrants I and IV.
__
1. sec(θ) = -√((-2)² +1) = -√5
2. cos(θ) = 1/sec(θ) = 1/(5/3) = 3/5
3. csc(θ) = -1/√(1 -(-3/5)²) = -√(16/25) = -4/5
