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beks73 [17]
3 years ago
12

Write an equation of a line in point-slope form with the

Mathematics
1 answer:
Ulleksa [173]3 years ago
4 0

Answer: (y − 0) = -(1/6)(x − 6)  or y=-(1/6)(x-6)

Step-by-step explanation:

An equation in Point Slope form:  y − y1 = m(x − x1), where m is the slope and x1 and y1 are provided as a single point, (x1,y1).  We have slope(m) = -(1/6) and are given (6,0).  Therefore:

 (y − 0) = -(1/6)(x − 6)  (Point slope form)

y = -(1/6)(x-6)

Rewriting this into standard form, y = mx + b

y = -(1/6)x + 1

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The circumference of a circle is 23π m. What is the area, in square meters? Express your answer in terms of \piπ
NARA [144]

Answer:

<h2>132.25π  m²</h2>

Step-by-step explanation:

The circumference of a circle is 23π

On the other hand, The circumference of a circle = 2×π×r ; where r is the radius.

then

by equating the last two expressions we get: 23π = 2πr then r = 23/2

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7 0
3 years ago
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Which is an x-intercept of the continuous function in the table?
Zielflug [23.3K]

Answer:

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Step-by-step explanation:

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3 years ago
Right triangle XYZ has right angle Z. If the sin(X)=1213<br> , what is the cos(X)
AlekseyPX

Given:

Right triangle XYZ has right angle Z.

\sin(x)=\dfrac{12}{13}

To find:

The value of \cos x.

Solution:

We know that,

\sin^2(x)+\cos^2(x)=1

\cos^2(x)=1-\sin^2(x)

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It is given that \sin(x)=\dfrac{12}{13}. After substituting this value in the above equation, we get

\cos(x)=\sqrt{1-(\dfrac{12}{13})^2}

\cos(x)=\sqrt{1-\dfrac{144}{169}}

\cos(x)=\sqrt{\dfrac{169-144}{169}}

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On further simplification, we get

\cos(x)=\dfrac{\sqrt{25}}{\sqrt{169}}

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Therefore, the required value is \cos(x)=\dfrac{5}{13}.

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3 years ago
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