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2 years ago

Can someone help me in question #5 please

Mathematics

1 answer:

Tamiku [17]2 years ago

6 0

Answer:

62 degrees

Step-by-step explanation:

Since lines i and k are parallel, angle b and h are interior angles and are equal to each other. Set up the equation by setting the two equal to each other.

8x-34=5x+2

Subtract 5x from both sides. (it cancels on the right side)

3x-34=2

Add 34 to both sides. (cancels on the left side)

3x=36

Divide both sides by 3.

x=12

Now plug it into either equation since they are equal. I'm gonna use the one for angle h so that it's less confusing.

5(12)+2

60+2

The measure of angle h is 62 degrees.

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The top of the cylindrical can shown below has a diameter of 7 centimeters (cm).

Zigmanuir [339]

Answer:

Step-by-step explanation:

3 0

2 years ago

The population of a town increased by 15% in 2016, and decreased by 5% in 2017. If the population of the town was 60,000 in the

nikdorinn [45]

Answer:

The population of the town at the end of 2017 was 65,550.

Step-by-step explanation:

The population of the town was 60,000 in the beginning of 2016.

In 2016, the total population is increased by 15%.

$60,000\times\frac{15}{100}=9000$

Therefore the population is increased by 9000 and the population of the town at the end of 2016 was

$60,000+9000=69,000$

In 2017, the total population is decreased by 5%.

$69,000\times\frac{5}{100}=3450$

Therefore the population is decreased by 3450 and the population of the town at the end of 2017 was

$69,000-3450=65,500$

Therefore the population of the town at the end of 2017 was 65,550.

3 0

3 years ago

Based on the model N(11541154,8686) describing steer weights, what are the cutoff values for a) the highest 10% of the we

yaroslaw [1]

Answer:

a) x = 1225.68

b) x = 1081.76

c) 1109.28 < x < 1198.72

Step-by-step explanation:

Given:

- Th random variable X for steer weight follows a normal distribution:

X~ N( 1154 , 86 )

Find:

a) the highest 10% of the weights?

b) the lowest 20% of the weights?

c) the middle 40% of the weights?

Solution:

We will compute the corresponding Z-value for highest cut off 10%:

Z @ 0.10 = 1.28

Z = (x-u) / sd

Where,

u: Mean of the distribution.

s.d: Standard deviation of the distribution.

1.28 = (x - 1154) / 86

x = 1.28*86 + 1154

x = 1225.68

We will compute the corresponding Z-value for lowest cut off 20%:

-Z @ 0.20 = -0.84

Z = (x-u) / sd

-0.84 = (x - 1154) / 86

x = -0.84*86 + 1154

x = 1081.76

We will compute the corresponding Z-value for middle cut off 40%:

Z @ 0.3 = -0.52

Z @ 0.7 = 0.52

[email protected] < x < [email protected]

-.52*86 + 1154 < x < 0.52*86 + 1154

1109.28 < x < 1198.72

7 0

2 years ago

Jada solved the equation Negative StartFraction 4 over 9 EndFraction = StartFraction x over 108 EndFraction for x using the step

Lilit [14]

Answer: First option.

Step-by-step explanation:

The complete exercise is attached.

In order to solve this exercise, it is necessary to remember the following property:

The Multiplication property of Equality states that:

$If\ a=b\ then\ a*c=b*c$

In this case, the equation that Jada had is the folllowing:

$-\frac{4}{9}=\frac{x}{108}$

Jada needed to solve for the variable "x" in order to find its value.

The correct procedure to solve for for "x" is to multiply both sides of the equation by 108. Then, you get:

$(108)(-\frac{4}{9})=(\frac{x}{108})(108)\\\\-48=x$

As you can notice in the picture, Jada did not multiply both sides of the equation by 108, but multiplied the left side by $-\frac{4}{9}$ <em> </em>and the right side by $-\frac{9}{4}$ .