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nexus9112 [7]
3 years ago
11

Ethan, Caleb, and Jayden went to a bakery to buy desserts. Ethan bought 2 cupcakes, 2

Mathematics
1 answer:
KIM [24]3 years ago
3 0

Answer:

x = 32

y = -20 and

z = -4

Step-by-step explanation:

Cupcakes = X

Brownies = Y

Pies = Z

Ethan = 2x+2y+z = 20

Caleb = 4x+4y+z = 44

Jayden = 5x+6y = 40

-1(2x+2y+z=20) =

(-2x - 2y - z = -40) + (4x+4y+z=44)

= 5x + 6y = 40

-3(2x+2y=24 =

(-6 - 6y = -72) + (5x + 6y = 40)

= - x = - 32

= x = 32

5 (32) + 6y = 40

= 160 + 6y = 40

6y = 40 - 160

y = 120/6

y = - 20

2(32) + 2(-20) + z = 20

64 - 40 + z = 20

z = 20 - 24

z = -4

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Answer:

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The value of 5 in 8395 is 10

To get the answer you have to do 1*10=10 so you would have to find a number where 5 is in the tens place

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The ratio of the width of a rectangle to it's length is 3:4. The length of the rectangle is 36 cm. Find the rectangles width.​
Fiesta28 [93]

Answer:

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So the ratio you have is

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3×9=27

You have 27:36

If you want to check it, divide both by 9 and you get 3:4

3 0
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musickatia [10]
Check the picture below.

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4 0
3 years ago
Read 2 more answers
Find the given higher-order derivative.<br><br> f''(x) = 9- 3/x<br><br> f'''(x)=
Genrish500 [490]

Answer:

f'''(x)=\frac{3}{x^{2}}

Step-by-step explanation:

We are given with Second-order derivative of function f(x).

f''(x)=9-\frac{3}{x}

We need to find Third-order derivative of the function f(x).

f''(x)=9-\frac{3}{x}=9-3x^{-1}

We know that,

f'''(x) = (f''(x))'

So,

f'''(x)=\frac{\mathrm{d}\,f''(x)}{\mathrm{d} x}

f'''(x)=\frac{\mathrm{d}\,(9-3x^{-1})}{\mathrm{d} x}

f'''(x)=\frac{\mathrm{d}\,9}{\mathrm{d} x}-\frac{\mathrm{d}\,3x^{-1}}{\mathrm{d} x}

f'''(x)=0-3\frac{\mathrm{d}\,x^{-1}}{\mathrm{d} x}

f'''(x)=-3(-1)x^{-1-1}

f'''(x)=3x^{-2}

f'''(x)=\frac{3}{x^{2}}

Therefore, f'''(x)=\frac{3}{x^{2}}

4 0
4 years ago
A test has 20 true/false questions. What is the probability that a student passes the test if they guess the answers? Passing me
Minchanka [31]

Using the binomial distribution, it is found that:

The probability that the student will get 15 correct questions in this test by guessing is 0.0207 = 2.07%.

For each question, there are only two possible outcomes, either the guess is correct, or it is not. The guess on a question is independent of any other question, hence, the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • There are 20 questions, hence n = 20.
  • Each question has 2 options, one of which is correct, hence p = \frac{1}{2} = 0.5

The probability is:

P(X \geq 15) = P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20)

In which:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 15) = C_{20,15}.(0.5)^{15}.(0.5)^{5} = 0.0148

P(X = 16) = C_{20,16}.(0.5)^{16}.(0.5)^{4} = 0.0046

P(X = 17) = C_{20,17}.(0.5)^{17}.(0.5)^{3} = 0.0011

P(X = 18) = C_{20,18}.(0.5)^{18}.(0.5)^{2} = 0.0002

P(X = 16) = C_{20,19}.(0.5)^{19}.(0.5)^{1} = 0

P(X = 17) = C_{20,20}.(0.5)^{20}.(0.5)^{0} = 0

Then:

P(X \geq 15) = P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20) = 0.0148 + 0.0046 + 0.0011 + 0.0002 + 0 + 0 = 0.0207

The probability that the student will get 15 correct questions in this test by guessing is 0.0207 = 2.07%.

You can learn more about the binomial distribution at brainly.com/question/24863377

6 0
3 years ago
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