4a + 3b - a - 5b
First, gather the like terms.
Second, subtract 4a - a to get 3a.
Third, subtract 3b - 5b to get 2b.
Answer:
3a - 2b
Answer:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Step-by-step explanation:
For this case first we need to create the sample of size 20 for the following distribution:
And we can use the following code: rnorm(20,50,6) and we got this output:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Answer:
Variance s2 = 788.33333
Standard Deviation s = 28.077274
Count n = 7
Mean x¯¯¯ = 52
Sum of Squares SS = 4730
Step-by-step explanation:
Step-by-step explanation:
It is (A)95° by using External Angle Property of triangles.
BTW whats up with that order C-D-B-A
Answer: the price of a senior citizen's ticket is $8.
the price of a child's ticket is $14
Step-by-step explanation:
Let x represent the price of a senior citizen's ticket.
Let y represent the price of a child's ticket.
On the first day of ticket sales, the school sold 3 senior citizen tickets and 1 child ticket for a total of $38. It means that
3x + y = 38- - - - - - - - - - - -1
The school took in $52 on the second day by selling 3 senior citizen and 2 child tickets. It means that
3x + 2y = 52- - - - - - - - - - - -2
Subtracting equation 2 from equation 1, it becomes
- y = - 14
y = 14
Substituting y = 14 into equation 1, it becomes
3x + 14 = 38
3x = 38 - 14 = 24
x = 24/3
x = 8
