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ycow [4]
3 years ago
8

What is −4 1/3 ÷( −2 3/5)

Mathematics
2 answers:
sladkih [1.3K]3 years ago
5 0

Answer:

5/3

Step-by-step explanation:

Hope I helped u

raketka [301]3 years ago
3 0

Answer:

5/3

1.6

Step-by-step explanation:

mixed number from: 1 2/4

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Find the distance between points P(5, 1) and Q(1, 3) to the nearest tenth.
bonufazy [111]

Answer:

Idk if its multiple choice but you can do 1 of 2 ways theres using distance formula =√(5-3)sq+(1-4)sq

=√4+9

=√13 <--

or

3.6 units

Given: The two points that are P(5,1) and Q(3,4).

To find: The distance between these two points.

Solution: It is given that there are two points that are P(5,1) and Q(3,4).

The distance between these two points can be found out as using the distance formula that is: 3.6

Thus, the distance between the given two points is 3.6 units.

So you choose 13 or 3.6 Hope this helps :)

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3 years ago
You deposit $3,348 into a savings account that earns 5% simple interest each year. If you save the money for 6 years, how much i
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Which type of function correctly describes the exponential function
Dennis_Churaev [7]

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3 0
4 years ago
Read 2 more answers
Jim and Andrew have 72 to bake. Jim bakes 1/2 of the cookies. Andrew bakes 4/9 cookies. How many cookies are left to bake?
Pavel [41]

Answer:

68 cookies

Step-by-step explanation:

72 x (1/2+4/9)= 68

There are 68 cookies left to bake

4 0
3 years ago
A square has a side length that is decreasing at a rate of 8 cm per second. What is the rate of change of the area of the square
Artist 52 [7]

Answer:

<h2><em>112cm²/sec</em></h2>

Step-by-step explanation:

Area of a square is expressed as A = L² where L is the length of one side of the square.

The rate of change of area will be expressed  using chain rule as;

dA/dt = dA/dL * dL/dt where;

dL/dt is the rate at which the side length of the square is decreasing.

Given L = 7cm, dL/dt = 8cm/sec and dA/dL = 2L

dA/dL = 2(7)

dA/dL = 14cm

Substituting the given value into the chain rule expression above to get the rate of change of the area of the square, we will have;

dA/dt = dA/dL * dL/dt

dA/dt = 14cm * 8cm/sec

dA/dt = 112cm²/sec

<em>Hence, the rate of change of the area of the square when the side length is 7 cm is 112cm²/sec</em>

<em></em>

8 0
4 years ago
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