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The second degree polynomial with leading coefficient of -2 and root 4 with multiplicity of 2 is:

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How to write the polynomial?</h3>
A polynomial of degree N, with the N roots {x₁, ..., xₙ} and a leading coefficient a is written as:

Here we know that the degree is 2, the only root is 4 (with a multiplicity of 2, this is equivalent to say that we have two roots at x = 4) and a leading coefficient equal to -2.
Then this polynomial is equal to:

If you want to learn more about polynomials:
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Since ZY bisects GE and XY bisects EF, and both ZY and XY both bisect GF, then XY ~ ZE and ZY ~ XE.
Therefore ZE = XY = 5
And GE = 2× ZE (because bisected segments are = and therefore ×2 = long segment).
So GE = 2ZE = 2×5 = 10
Answer:
option C: 120
Step-by-step explanation:
total marks = 5× 100 = 500
marks he obtained = 380
marks he lost = 500 - 380 = 120
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