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3 years ago

9

Then when you expand it can u simplify it and tell me the coefficient and variable and constant 3(y-6)+4(5+4)-8(y-2)

1 answer:

madreJ [45]3 years ago

6 0

Cymath es una buena aplicación para tus dudas de matemática

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PLEASE HELP ASAPPP !! Instructions: State what additional information is required in order to know that the triangles are congru

Svetllana [295]

<h3>Answer: angle T = angle W</h3>

Explanation:

We are given the sides are congruent due to the tickmarks. Specifically

TU = WV (single tickmarks)

TV = WX (double tickmarks)

So we just need the "A" of "SAS". The A is between the two S letters, so the angle is between the two sides. For triangle TUV, the angle T is between the two sides with the tickmarks. Similarly, angle W is between the tickmarked sides of triangle WVX.

If we know that angle T = angle W, then we have enough information to use SAS.

5 0

4 years ago

In Exercises 5-7, find all the exact t-values for which the given statement is true,

bearhunter [10]

Answer: See Below

<u>Step-by-step explanation:</u>

NOTE: You need the Unit Circle to answer these (attached)

5) cos (t) = 1

Where on the Unit Circle does cos = 1?

Answer: at 0π (0°) and all rotations of 2π (360°)

In radians: t = 0π + 2πn

In degrees: t = 0° + 360n

******************************************************************************

$6)\quad sin (t) = \dfrac{1}{2}$

Where on the Unit Circle does $sin = \dfrac{1}{2}$

<em>Hint: sin is only positive in Quadrants I and II</em>

$\text{Answer: at}\ \dfrac{\pi}{6}\ (30^o)\ \text{and at}\ \dfrac{5\pi}{6}\ (150^o)\ \text{and all rotations of}\ 2\pi \ (360^o)$

$\text{In radians:}\ t = \dfrac{\pi}{6} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{6} + 2\pi n$

In degrees: t = 30° + 360n and 150° + 360n

******************************************************************************

$7)\quad tan (t) = -\sqrt3$

Where on the Unit Circle does $\dfrac{sin}{cos} = \dfrac{-\sqrt3}{1}\ or\ \dfrac{\sqrt3}{-1}\quad \rightarrow \quad (1,-\sqrt3)\ or\ (-1, \sqrt3)$

<em>Hint: sin and cos are only opposite signs in Quadrants II and IV</em>

$\text{Answer: at}\ \dfrac{2\pi}{3}\ (120^o)\ \text{and at}\ \dfrac{5\pi}{3}\ (300^o)\ \text{and all rotations of}\ 2\pi \ (360^o)$

$\text{In radians:}\ t = \dfrac{2\pi}{3} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{3} + 2\pi n$

In degrees: t = 120° + 360n and 300° + 360n

4 0

3 years ago

Explain why this quadrilateral is not a parallelogram.

ladessa [460]

Answer:

because this figure does not have two parallel sides

I'm Sorry for by bad English but I am italian

8 0

3 years ago

60 POINTS AND BRAINLIEST!!!!!

ser-zykov [4K]

SOLUTION:

3y - 24 = 237

3y = 237 + 24

3y = 261

y = 261 / 3

y = 87

Hope this helps! :)
Have a lovely day! <3

5 0

3 years ago

Who walked the shortest distance on the trail?

solmaris [256]

Answer:

charles

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers