Answer:
0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:
In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Over a long period of time, an average of 14 particles per minute occurs. Assume the arrival of particles at the counter follows a Poisson distribution. Find the probability that at least one particle arrives in a particular one second period.
Each minute has 60 seconds, so 
Either no particle arrives, or at least one does. The sum of the probabilities of these events is decimal 1. So
We want 
. So
In which
0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.
Answer:
Step-by-step explanation:
Hope this helps!
Once per month there is food that is 33 centimeters long
Answer:
C=6p
Step-by-step explanation:
The cost (c) will be by itself since that is the answer you are looking for. 6p is grouped together because for every pound you pay $6. For example if you had 2 pounds of chocolate. You would multiple $6 by 2 and your cost would equal $12
Domain includes all the x-values in the function. Range includes all the y-values in the function.
The first table has x-values of -1, 3, and 6, and y-values of 4, 5, and 6. This means that the domain and range would be given by the following sets:
Domain: {-1, 3, 6}
Range: {4, 5, 6}
The second set of points has x-values of -4, -4, -3, and 1, and y-values of 1, 1, 3, and 4. Duplicate points are not listed within the domain and range, so the domain and range would be given by the following sets:
Domain: {-4, -3, 1}
Range: {1, 3, 4}
