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mr Goodwill [35]

3 years ago

11

12. Which equation has no solution?

1 answer:

alexandr1967 [171]3 years ago

6 0

B 24a-22=-4(1-6a) has no solution

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Help please!!!!!!!!!!

adell [148]

Answer:

1/2?

Step-by-step explanation:

8 0

3 years ago

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Afirm will break even (no profit and no loss) as long as revenue just equals cost. The value of x (the number of items produced

s2008m [1.1K]

Cost function, $C(x)=300+15x$

Revenue function, $R(x) = 30x$

Profit function, $P(x)=15x-300$

Break point $x=20$ .

Fixed cost $=$ $ $300$ .

Variable cost $=$ $ $15$ .

Price of item $=$ $ $30$ .

Let $x$ be the number of items produced and sold.

a) Cost function $=$ Fixed cost $+$ variable cost \times number of items

So, $C(x)=300+15x$

b) Revenue $=$ Price of an item $\times$ number of items

So, $R(x) = 30x$

c) Profit $=$ Revenue $-$ Cost

$P(x)=R(x)-C(x)$

$P(x)=30x-300-15x$

$P(x)=15x-300$

d) <u>Break even point</u> $R(x)=C(x)$

$30x=300+15x$

$30x-15x=300$

$15x=300$

$x=20$ .

So, the product should be produced for $20$ or more items.

Learn more about cost function here:

brainly.com/question/13129990?referrer=searchResults

8 0

2 years ago

What is the factored form of x^12y^18+1

Black_prince [1.1K]

Answer: The required factored form of the given expression is

$(x^4y^6+1)(x^8y^{12}-x^4y^6+1).$

Step-by-step explanation: We are given to find the factored form of the following algebraic expression:

$E=x^{12}y^{18}+1.$

We will be using the following formula:

$a^3+b^3=(a+b)(a^2+ab+b^2).$

Now, we have

$E\\\\=x^{12}y^{18}+1\\\\=(x^4y^6)^3+1^3\\\\=(x^4y^6+1)\{(x^4y^6)^2-x^4y^6\times1+1^2\}\\\\=(x^4y^6+1)(x^8y^{12}-x^4y^6+1).$

Thus, the required factored form of the given expression is

$(x^4y^6+1)(x^8y^{12}-x^4y^6+1).$

4 0

3 years ago

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Can someone help me with number 28

notsponge [240]

61/66=0.9242 So in % that is %92.42

3 0

3 years ago

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Choose all the numbers that are part of Integers.

sweet-ann [11.9K]

Answer:

1 ,0

Step-by-step explanation:

Because They aren't negitive nor repeating

6 0

4 years ago

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