All categories

3 years ago

IM BEGGING YOU PLEASE ANSWER EASY MATH QUESTIOON!!!!

Mathematics

2 answers:

maw [93]3 years ago

5 0

The answer you chose is correct.
The slope is 10 because for each newspaper, she earns an additional $10.

When there are no newspapers, she earns a $125 salary.

Final answer: A

aniked [119]3 years ago

5 0

The correct answer would be A. 10x+125 because if you do this for any given x-value on the chart, you will get the corresponding y-value.

You might be interested in

The sum of the measures of 2 exterior angles is 264°. What is the measure of the third exterior angle?

erma4kov [3.2K]

Well if all angles are suppose to add up to 360 degrees you can the angles to see if the equal up to 360 degrees, 264+96=360.

3 0

3 years ago

Find the area of the figure. Use 3.14 for it.

Tcecarenko [31]

Answer:

963.73 m²

Step-by-step explanation:

To Find :-

Area of the figure

Solving :-

Area (figure) = Area (triangle) + Area (semicircle)

= 1/2bh + 1/2πr²

= 1/2 (30 x 34 + 3.14 x 17 x 17)

= 1/2 (1020 + 289 x 3.14)

= 1/2 (1020 + 907.46)

= 1/2 (1927.46)

= 963.73 m²

4 0

2 years ago

Will someone please explain step by step how i'm suppose to solve this cuz I don't know what i'm doing. Thanks in advance.

kumpel [21]

I believe it's (-1,-3)
I hope this helps

6 0

3 years ago

Iggy wants to purchase a six-cylinder sports car that costs $15,690. The dealer is offering either a $3,500 instant rebate or 20

olganol [36]

$12552 because after rebate $3,138 would be reduced from the price making the ending price be $12,552

5 0

3 years ago

Find the area of the surface. the part of the plane 4x + 4y + z = 16 that lies inside the cylinder x2 + y2 = 9

MAVERICK [17]

As a first step, convert to cylindrical coordinates. The equation $x^2+y^2=9=3^2$ is a clue to set

$x=3r\cos\theta$

$y=3r\sin\theta$

then have $0\le r\le1$ and $0\le\theta\le2\pi$ . Meanwhile, the plane equation tells you to use

$4x+4y+z=16\implies z=16-12r\cos\theta-12r\sin\theta$

So we parameterize the part of the plane within the cylinder with the vector-valued function

$\mathbf s(r,\theta)=(3r\cos\theta,3r\sin\theta,15-12r\cos\theta-12r\sin\theta)$

The surface integral giving the area of the surface is

$\displaystyle\iint_{\mathcal S}\mathrm dS$

where $\mathcal S$ denotes the surface in question, and the surface element $\mathrm dS$ is

$\mathrm dS=\left\|\dfrac{\partial\mathbf s}{\partial r}\times\dfrac{\partial\mathbf s}{\partial\theta}\right\|\,\mathrm dr\,\mathrm d\theta$

We have

$\dfrac{\partial\mathbf s}{\partial r}=(3\cos\theta,3\sin\theta,-12(\cos\theta+\sin\theta))$

$\dfrac{\partial\mathbf s}{\partial\theta}=(-3r\sin\theta,3r\cos\theta,12r(\sin\theta-\cos\theta))$

$\implies\mathrm dS=\|(36r,36r,9r\|\,\mathrm dr\,\mathrm d\theta=9\sqrt{33}r\,\mathrm dr\,\mathrm d\theta$

So the area is

$\displaystyle\iint_{\mathcal S}\mathrm dS=9\sqrt{33}\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}r\,\mathrm dr\,\mathrm d\theta=18\sqrt{33}\,\pi$

4 0

3 years ago