The value of numerators are 3 and 5
<em><u>Solution:</u></em>
Let the numerators of two fractions be x and y
Two fractions have denominators 4 and 6. Their sum is 19/12
Therefore,
Cross multiply L.H.S to get simplified
If the numerators are switched their sum is 7/4
Therefore,
On simplification, we get
<em><u>Solve eqn 1 and eqn 2</u></em>
<em><u>Multiply eqn 1 by 4</u></em>
24x + 16y = 152 --------- eqn 3
Multiply eqn 2 by 6
24x + 36y = 252 ---------- eqn 4
<em><u>Subtract eqn 3 from eqn 4</u></em>
24x + 36y = 252
24x + 16y = 152
( - ) -------------------
20y = 100
<h3>y = 5</h3>
<em><u>Substitute y = 5 in eqn 1</u></em>
6x + 4(5) = 38
6x = 38 - 20
6x = 18
<h3>x = 3</h3>
Thus the value of numerators are 3 and 5
37/40
bc (37+29+26+32+38+35+34+39)/8 = 35
X=2 Y=6 because we did this last week and I stilll have mine
Differences:
If the a≠1, then instead of finding two numbers that when multiplied equal c and when added equal b (which is the a=1 situation), you are looking for two numbers which when multiplied equal ac and add up to be b.
When finding the two numbers for a≠1, you cannot just plug the two numbers into (x+__)(x+__), you have to extend the b term into those two numbers.
After extending the b term into the two terms, you then have to group them and take out the GCF's unlike in an a=1 situation.
Similarities:
The first step for both is finding two terms which equal b if added.
Once factored, you have to set the factored sections to zero if you wish to find the solutions.
Before finding the two terms which equal b if added, you should take out any GCF's from the overall equation.
Answer: Multiplication takes precedence
Execute the command multiplication bracket
3x + 2* (x - 1) - 4 =
3x + 2* x + 2* (-1 ) - 4 =
3x + 2x - 2 - 4 =
Step-by-step explanation:
