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jeka57 [31]
2 years ago
15

What is the range of the function f(x) = 3x2 + 6x – 8?

Mathematics
2 answers:
ikadub [295]2 years ago
8 0
The range of the function f(x) = 3x^2 + 6x - 8 is <span>{y|y ≥ –11}</span>
guajiro [1.7K]2 years ago
7 0

Answer:

The range of the function f(x)=3x²+6x-8 is:

{y|y ≥ –11}

Step-by-step explanation:

The function f(x)=3x²+6x-8 could also be written as:

f(x)=3x²+6x+3-11

f(x)=3(x²+2x+1)-11

f(x)=3(x+1)²-11

as we know that the value of 3(x+1)²≥0

Then, the value of 3(x+1)²-11≥-11

i.e. f(x)≥-11

Hence, the range of the function f(x)=3x²+6x-8 is:

{y|y ≥ –11}

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In a right triangle abc, cd is an altitude, such that ad=bc. Find ac, if ab=3 cm, and cd= square root 2 cm.
Mashcka [7]

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7 0
3 years ago
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