What is the range of the function f(x) = 3x2 + 6x – 8?
2 answers:
The range of the function f(x) = 3x^2 + 6x - 8 is <span>{y|y ≥ –11}</span>
Answer:
The range of the function f(x)=3x²+6x-8 is:
{y|y ≥ –11}
Step-by-step explanation:
The function f(x)=3x²+6x-8 could also be written as:
f(x)=3x²+6x+3-11
f(x)=3(x²+2x+1)-11
f(x)=3(x+1)²-11
as we know that the value of 3(x+1)²≥0
Then, the value of 3(x+1)²-11≥-11
i.e. f(x)≥-11
Hence, the range of the function f(x)=3x²+6x-8 is:
{y|y ≥ –11}
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Answer:
A.x+5=6x
Step 1:subtract 6x from both sides.
x+5-6x=6x-6x
-5x+5=0
Step 2:subtract 5 from both sides.
-5x+5-5=0-5
-5x=-5
Step 3:divide both by -5
-5x/5=-5/5
X=1