Not sure if the equation is
![\log_9x+\log_3(x^2)=\dfrac52](https://tex.z-dn.net/?f=%5Clog_9x%2B%5Clog_3%28x%5E2%29%3D%5Cdfrac52)
or
![\log_x9+\log_{x^2}3=\dfrac52](https://tex.z-dn.net/?f=%5Clog_x9%2B%5Clog_%7Bx%5E2%7D3%3D%5Cdfrac52)
![9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot9^{\log_3(x^2)}](https://tex.z-dn.net/?f=9%5E%7B%5Clog_9x%2B%5Clog_3%28x%5E2%29%7D%3D9%5E%7B%5Clog_9x%7D%5Ccdot9%5E%7B%5Clog_3%28x%5E2%29%7D)
![9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot(3^2)^{\log_3(x^2)}](https://tex.z-dn.net/?f=9%5E%7B%5Clog_9x%2B%5Clog_3%28x%5E2%29%7D%3D9%5E%7B%5Clog_9x%7D%5Ccdot%283%5E2%29%5E%7B%5Clog_3%28x%5E2%29%7D)
![9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot3^{2\log_3(x^2)}](https://tex.z-dn.net/?f=9%5E%7B%5Clog_9x%2B%5Clog_3%28x%5E2%29%7D%3D9%5E%7B%5Clog_9x%7D%5Ccdot3%5E%7B2%5Clog_3%28x%5E2%29%7D)
![9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot3^{\log_3(x^2)^2}](https://tex.z-dn.net/?f=9%5E%7B%5Clog_9x%2B%5Clog_3%28x%5E2%29%7D%3D9%5E%7B%5Clog_9x%7D%5Ccdot3%5E%7B%5Clog_3%28x%5E2%29%5E2%7D)
![9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot3^{\log_3(x^4)}](https://tex.z-dn.net/?f=9%5E%7B%5Clog_9x%2B%5Clog_3%28x%5E2%29%7D%3D9%5E%7B%5Clog_9x%7D%5Ccdot3%5E%7B%5Clog_3%28x%5E4%29%7D)
![9^{\log_9x+\log_3(x^2)}=x\cdot x^4](https://tex.z-dn.net/?f=9%5E%7B%5Clog_9x%2B%5Clog_3%28x%5E2%29%7D%3Dx%5Ccdot%20x%5E4)
![9^{\log_9x+\log_3(x^2)}=x^5](https://tex.z-dn.net/?f=9%5E%7B%5Clog_9x%2B%5Clog_3%28x%5E2%29%7D%3Dx%5E5)
On the other side of the equation, we'd get
![9^{5/2}=(3^2)^{5/2}=3^{2\cdot(5/2)}=3^5](https://tex.z-dn.net/?f=9%5E%7B5%2F2%7D%3D%283%5E2%29%5E%7B5%2F2%7D%3D3%5E%7B2%5Ccdot%285%2F2%29%7D%3D3%5E5)
Then
![x^5=3^5\implies\boxed{x=3}](https://tex.z-dn.net/?f=x%5E5%3D3%5E5%5Cimplies%5Cboxed%7Bx%3D3%7D)
- If it's the second one instead, you can use the same strategy as above:
![x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot x^{\log_{x^2}3}](https://tex.z-dn.net/?f=x%5E%7B%5Clog_x9%2B%5Clog_%7Bx%5E2%7D3%7D%3Dx%5E%7B%5Clog_x9%7D%5Ccdot%20x%5E%7B%5Clog_%7Bx%5E2%7D3%7D)
![x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot\left((x^2)^{1/2}\right)^{\log_{x^2}3}](https://tex.z-dn.net/?f=x%5E%7B%5Clog_x9%2B%5Clog_%7Bx%5E2%7D3%7D%3Dx%5E%7B%5Clog_x9%7D%5Ccdot%5Cleft%28%28x%5E2%29%5E%7B1%2F2%7D%5Cright%29%5E%7B%5Clog_%7Bx%5E2%7D3%7D)
(Note that this step assume
)
![x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot(x^2)^{(1/2)\log_{x^2}3}](https://tex.z-dn.net/?f=x%5E%7B%5Clog_x9%2B%5Clog_%7Bx%5E2%7D3%7D%3Dx%5E%7B%5Clog_x9%7D%5Ccdot%28x%5E2%29%5E%7B%281%2F2%29%5Clog_%7Bx%5E2%7D3%7D)
![x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot(x^2)^{\log_{x^2}\sqrt3}](https://tex.z-dn.net/?f=x%5E%7B%5Clog_x9%2B%5Clog_%7Bx%5E2%7D3%7D%3Dx%5E%7B%5Clog_x9%7D%5Ccdot%28x%5E2%29%5E%7B%5Clog_%7Bx%5E2%7D%5Csqrt3%7D)
![x^{\log_x9+\log_{x^2}3}=9\sqrt3](https://tex.z-dn.net/?f=x%5E%7B%5Clog_x9%2B%5Clog_%7Bx%5E2%7D3%7D%3D9%5Csqrt3)
Then we get
![9\sqrt3=x^{5/2}\implies x=(9\sqrt3)^{2/5}\implies\boxed{x=3}](https://tex.z-dn.net/?f=9%5Csqrt3%3Dx%5E%7B5%2F2%7D%5Cimplies%20x%3D%289%5Csqrt3%29%5E%7B2%2F5%7D%5Cimplies%5Cboxed%7Bx%3D3%7D)
Answer: 160lbs
Step-by-step explanation:
432/100 is 4.32
4.32x45 is 194.4
answer: $194.40
The point-slope form of a line is:
y-y1=m(x-x1), where m is the slope of the line and (x1,y1) is any point on the line.
In this case x1=7 and y1=-2 so the point used to create this equation is:
(7, -2)
Answer:
it is not possible you cannot divide by zero