(8x^2+2x+8)+(3x^3+7x+4)=
8x^2+2x+8+3x^3+7x+4
3x^3+8x^2+(2+7)x+12=
3x^3+8x^2+9x+12
Answer: Option A. 3x^3+8x^2+9x+12
1.) calculate the quotient
2.)calculate the product
3.)factor out y from the expression
I got yx(2xy-8x^2+3y^3)
X=<span><span><span><span>−4/</span>3</span>y</span>+<span><span>−8/</span><span>3
and
</span></span></span>x=<span><span><span><span>−4/</span>3</span>y</span>+<span>10/<span>9</span></span></span>
Answer: 16 • (x - 2) • (x + 2) • (x - 5)
Step-by-step explanation: 1
(((2•(x-2)•(x+2))•4)•(x-5))•2
STEP
2
:
Equation at the end of step 2
((2•(x-2)•(x+2)•4)•(x-5))•2
STEP
3
:
Equation at the end of step 3
(8 • (x - 2) • (x + 2) • (x - 5)) • 2
STEP
4
:
Equation at the end of step 4
8 • (x - 2) • (x + 2) • (x - 5) • 2
STEP
5
:
Final result :
16 • (x - 2) • (x + 2) • (x - 5)