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trasher [3.6K]
3 years ago
7

Identify the scale factor used to graph the image below .

Mathematics
1 answer:
den301095 [7]3 years ago
7 0

Answer:

It increased by a scale factor of 4

Step-by-step explanation:

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The graph of the equation below is a circle. What is the length of the radius of the circle? (x - 4)^2 + (y + 12)^2 = 17^2
djverab [1.8K]
The correct answer is:  [D]:  "17" .
______________________________________________________
The radius is:  " 17" .
______________________________________________________
Note:
______________________________________________________
The formula/equation for the graph of a circle is:
______________________________________________________
   (x − h)²  +<span> </span> (y − k)² =  r²  ;

in which:  

          " (h, k) " ; are the coordinate of the point of the center of the circle;

           "r" is the length of the "radius" ; for which we want to determine;
_______________________________________________________
We are given the following equation of the graph of a particular circle:
_______________________________________________________

          →  (x − 4)²  +  (y + 12)² =  17² ;

which is in the correct form:

→  " (x − h)²  +  (y − k)² =  r²  " ;

 in which:  " h = 4 " ;

                  " k = -12" ;

                   "r = 17 " ;  which is the "radius" ; which is our answer.

          →  { Note that: "k = NEGATIVE  12" } ;

→  Since the equation <u>for this particular circle</u> contains the expression:             _________________________________________________________    
                      →     "...(y + k)² ..." ;  
         
[as opposed to the standard form:  "...(y − k)² ..." ] ; 
_________________________________________________________
→  And since the coordinates of the center of a circle are represented by:
            " (h, k) " ;  
 
→  which are:  " (4, -12) " ;  (<u>for this particular circle</u>) ; 
_________________________________________________________
→  And since:  " k = -12 " ;  (<u>for this particular circle</u>) ;
_________________________________________________________
then: 

 " [y − k ] ²  =  [ y − (k) ] ²  =  " [ y − (-12) ] ² " ;
                                    
                                         =  " ( y + 12)² "  ;
                                    
{NOTE:  Since:  "subtracting a negative" is the same as "adding a positive" ;

           →   So;  " [ y − (-12 ] " = " [ y + (⁺ 12) ] " = " (y + 12) "
___________________________________________________  
Note:  The above explanation is relevant to confirm that the equation is, in fact, in "proper form"; to ensure that the:  radius, "r" ;  is:  "17" .
___________________________________________________
           →    Since:  "r  =  17 " ;  

           →  The radius is:  " 17 " ;

          which is:  Answer choice:  [D]:  "17" .
___________________________________________________
8 0
3 years ago
Read 2 more answers
If , find the value of 2 square root of 17-x = 2x-10, find the value of x/4.
ira [324]
2 \sqrt{17-x} =2x-10\ \ \ \ \Rightarrow\ \ \ D:(17-x \geq 0\ \ \ and\ \ \ 2x-10 \geq 0)\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x \leq 17\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ x \geq 5\\\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ D=\\\\2 \sqrt{17-x} =2(x-5)\ /:2\\\\ \sqrt{17-x} =x-5\ \ \ \Rightarrow\ \ \ (\sqrt{17-x})^2 =(x-5)^2\\\\17-x=x^2-10x+25\\\\

x^2-9x+18=0\\\\ x^2-3x-6x+18=0\\\\x(x-3)-6(x-3)=0\\\\(x-3)(x-6)=0\ \ \ \ \Leftrightarrow\ \ \ (x-3=0\ \ \ \ or\ \ \ \ x-6=0)\\\\x=3\ \notin\ D\ \ \ \ \ \ \ \ \ \ \ x=6\ \in\ D\ \ \ \Rightarrow\ \ \  \frac{x}{4} = \frac{6}{4} =1.5\\\\Ans.\  \frac{x}{4} =1.5
7 0
3 years ago
Find the vertex of y=-x^2-4x
Kay [80]
The vertex would be (-2,4)
3 0
4 years ago
Synthetic Division x^3+9x^2-11x-13
olga nikolaevna [1]

Answer:

You can't synthetic divide since there's no dividend. As you can't factor it so I figure you must've forgot to include something or there's no solution.

8 0
3 years ago
Write an expression that represent the sum of a number and 12
antiseptic1488 [7]

Answer:

5+12

there is no equals sign in an expression so it is just that



6 0
3 years ago
Read 2 more answers
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