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bonufazy [111]
4 years ago
13

If the annual proportion of erroneous income tax returns filed with the IRS can be looked upon as a random variable having a bet

a distribution with α = 2 and β = 9, what is the probability that in any given year there will be fewer than 10 percent erroneous returns?

Mathematics
1 answer:
Volgvan4 years ago
8 0

Answer:

The probability that in any given year there will be fewer than 10 percent erroneous returns is P(x≤0.1)=0.264.

Step-by-step explanation:

For a beta distribution with α = 2 and β = 9, we need to use a calculator to compute the probabilities.

The probability that in any given year there will be fewer than 10 percent erroneous returns is P(x≤0.1)=0.264.

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3 years ago
OBSERVATION A person standing 100 feet from the bottom of a cliff notices a tower on top of the cliff. The angle of elevation to
vekshin1

Answer:

The tower is 102.26 feet tall.

Step-by-step explanation:

We have drawn the triangle for your reference.

According to the figure point 'A' is the persons eye.

Point 'B' is the bottom of the cliff.

Point 'C' is the top of the cliff.

And Point 'D' is the top of the tower.

Given,

A person standing 100 feet from the bottom of a cliff notices a tower on top of the cliff.

So from diagram we can say that;

Length of AB = 100 ft

The angle of elevation to the top of the cliff is 30°.

So from diagram we can say that;

∠CAB = 30°

the angle of elevation to the top of the tower is 58°.

So from diagram we can say that;

∠DAB = 58°

We have to find the height of the tower i.e. CD.

Solution,

In ΔCAB,

∠CAB = 30°

AB = 100 ft

Now according to trigonometric  ratios;

tan\theta=\frac{opposite\ side}{adjacent\ side}

Substituting the values we get;

tan\ 30\° = \frac{BC}{100}

Now

tan\ 30\° = \frac{1}{\sqrt{3}}

So

\frac{1}{\sqrt{3}} = \frac{BC}{100}\\\\BC =\frac{100}{\sqrt{3}} = 57.74 \ ft

In ΔDAB,

∠DAB = 58°

AB = 100 ft

Now according to trigonometric  ratios;

tan\theta=\frac{opposite\ side}{adjacent\ side}

Substituting the values we get;

tan\ 58\° = \frac{BD}{100}

Now

tan\ 58\° = 1.60

So

1.60 = \frac{BD}{100}\\\\BD =100\times 1.6 = 160 \ ft

Now BD = BC + CD

CD = BD - BC = 160 - 57.74 = 102.26 ft

Hence The tower is 102.26 feet tall.

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Answer:

Step-by-step explanation:

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