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LekaFEV [45]
3 years ago
12

Olivia signed up for a streaming music service where there's a fixed cost for monthly membership and a cost per song downloaded.

Her total cost per month is given by the equation c=4.99+0.75x, where x represents the number of songs she downloads and cc represents the total cost, in dollars and cents. What could the number 0.75 represent in the equation?

Mathematics
2 answers:
Nuetrik [128]3 years ago
8 0

Answer:

(A)If x represents the number of songs she downloads then it is a variable because of the AMOUNT of songs she downloads.

Step-by-step explanation:

For example if we had f(x)=2 the equation would be c=4.99+.75(2)

.75*2=1.50+4.99=

(6.49 = c) cost per month if she downloads 2 songs

Nata [24]3 years ago
8 0

Answer:

Option Number 1

Step-by-step explanation:

The total cost per month is written as c = 4.99 + 0.75x

We are given that x is the number of songs downloaded

The base price per month is 4.99

So the cost per month is 4.99 PLUS the amount of songs multiplied by 0.75. That means 0.75 is the price per song.

-Chetan K

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Find the smallest relation containing the relation {(1, 2), (1, 4), (3, 3), (4, 1)} that is:
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Remember, if B is a set, R is a relation in B and a is related with b (aRb or (a,b))

1. R is reflexive if for each element a∈B, aRa.

2. R is symmetric if satisfies that if aRb then bRa.

3. R is transitive if satisfies that if aRb and bRc then aRc.

Then, our set B is \{1,2,3,4\}.

a) We need to find a relation R reflexive and transitive that contain the relation R1=\{(1, 2), (1, 4), (3, 3), (4, 1)\}

Then, we need:

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2. Observe that

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Therefore \{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(4,1),(4,2)\} is the smallest relation containing the relation R1.

b) We need a new relation symmetric and transitive, then

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and the analysis for be transitive is the same that we did in a).

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Therefore, the smallest relation containing R1 that is symmetric and transitive is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

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  • 3 must be related with 3,
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  • since 1R4, 4 must be related with 1.

For be transitive

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Then, the smallest relation reflexive, symmetric and transitive containing R1 is

\{(1,1),(2,2),(3,3),(4,4),(1,2),(1,4),(2,1),(2,4),(3,3),(4,1),(4,2),(4,4)\}

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