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2 years ago

A dog gave birth to 9 puppies, of which 2 are brindle. What is the ratio of brindle puppies to non-brindled puppies?

Mathematics

1 answer:

Alborosie2 years ago

7 0

Answer:

2:7

Step-by-step explanation:

If 2 of the puppies are brindle that leaves 7 that are not out of the nine making the ratio 2:7.

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1. Oxygen has an electronegativity of 3.5, and carbon has an electronegativity of 2.5. How is charge distributed on an oxygen at

torisob [31]

Answer:

Step-by-step explanation:

because 1 was removed from it

7 0

3 years ago

Please help... Solve using the quadratic formula x^2 - 6x - 40=0

Tasya [4]

The answer is

X=10 or X= -4

6 0

3 years ago

Analyze the diagram below and complete the instructions that

Novosadov [1.4K]

9514 1404 393

Answer:

D. x = 15; y = 5√3

Step-by-step explanation:

You don't need to know any trig to select the correct answer. You only need to know that the lengths of both sides must be less than the length of the hypotenuse. It is also helpful to know that √3 is about 1.732, so 10√3 ≈ 17.32.

Since x < 10√3, only answer choices A and D are viable.

Since y < 10√3, only answer choice D is viable.

_____

If you want to solve this using trig relations, you can recall that the sides of a 30°-60°-90° triangle have the ratios 1 : √3 : 2. This means short side y is half the length of the hypotenuse 10√3, so y = 5√3. It also means longer side x is √3 times y, so is x = (5√3)√3 = 5·3 = 15.

x = 15; y = 5√3

6 0

3 years ago

Use the divergence theorem to calculate the surface integral s f · ds; that is, calculate the flux of f across s. f(x, y, z) = x

valkas [14]

$\mathbf f(x,y,z)=x^4\,\mathbf i-x^3z^2\,\mathbf j+4xy^2z\,\mathbf k$
$\mathrm{div}(\mathbf f)=\dfrac{\partial(x^4)}{\partial x}+\dfrac{\partial(-x^3z^2)}{\partial y}+\dfrac{\partial(4xy^2z)}{\partial z}=4x^3+0+4xy^2=4x(x^2+y^2)$

Let $\mathcal D$ be the region whose boundary is $\mathcal S$ . Then by the divergence theorem,

$\displaystyle\iint_{\mathcal S}\mathbf f\cdot\mathrm d\mathbf S=\iiint_{\mathcal D}4x(x^2+y^2)\,\mathrm dV$

Convert to cylindrical coordinates, setting

$x=r\cos\theta$
$y=r\sin\theta$

and keeping $z$ as is. Then the volume element becomes

$\mathrm dV=r\,\mathrm dr\,\mathrm d\theta\,\mathrm dz$

and the integral is

$\displaystyle\iiint_{\mathcal D}4x(x^2+y^2)\,\mathrm dV=\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=0}^{z=r\cos\theta+7}4r\cos\theta\cdot r^2\cdot r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\displaystyle4\iiint_{\mathcal D}r^4\cos\theta\,\mathrm dz\,\mathrm dr\,\mathrm d\theta$
$=\dfrac{2\pi}3$

4 0

4 years ago

Question in picture solve

mash [69]

Answer: Choice B) 7/2 and choice D) 2

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3 years ago