There are 4! = 24 poosible permutations of the four letters. Let the letters be A, B, C and D. Two permutations will have only letter A in the correct envelope, two more permutations will have only letter B in the correct envelope, two more will have only letter C in the correct envelope and two more will have only letter D in the correct envelope. Therefore 8 out of the 24 possible permutations will have only one letter with the correct address. The required probability is 8/24 = 1/3.
P(red) = 9/(9 + 7 + 11) = 9/27 = 1/3
P(green) = 7/27
P(red or green) = 1/3 + 7/27 = 16/27
Day: Monday, Tuesday, Wednesday, Thursday, Friday
frequency: 3, 1, 1, 1, 5
Frequency is the repeated number of times so you just need to count how many times a day repeats.
Answer:
it is -12, -6, -4, -3, 1, 4
A.
Step-by-step explanation:
It's exactly what's asked for.