Answer:
Q1: p = - 33
Q2: d = - 99
Q3: t = - 13
Step-by-step explanation:
Q1: 
We solve this taking LCM.
We get: 
Q4: 
Again we proceed like Q1 by taking LCM.
We get: 
Q7: 5t + 12 = 4t - 1
We club the like terms on either side.
Hence, the answer.
A is the answer since if you graph it, it has those points, or you may just simply plug in the x points that are given and see if they equal the y number
The roots are 1 +√7 and 1 -√7.
<h3>What is Quadratic equation?</h3>
A quadratic equation in the variable x is an equation of the form ax² + bx + c= 0, where a, b, c are real numbers, a≠0
Given equation:
y= x²+2x-6
First,
Half the coefficient of x and add and subtract the square of (b/2)
y= x²+2x-6+(1)²-(1)²
y= x²+2x+(1)² -6 -(1)²
y= (x+1)² -7
Now, equate y=0
(x+1)² -7 =0
(x+1)² = 7
x+1= ±√7
x=1 ±√7
Hence, the roots are 1 +√7 and 1 -√7.
Learn more about quadratic equation here:
brainly.com/question/1962219
#SPJ1
Answer:
we have (a,b,c)=(4,-2,0) and R=4 (radius)
Step-by-step explanation:
since
x²+y²+z²−8x+4y=−4
we have to complete the squares to finish with a equation of the form
(x-a)²+(y-b)²+(z-c)²=R²
that is the equation of a sphere of radius R and centre in (a,b,c)
thus
x²+y²+z²−8x+4y=−4
x²+y²+z²−8x+4y +4 = 0
x²+y²+z²−8x+4y +4 +16-16 =0
(x²−8x + 16) + (y² + 4y + 4 ) + (z²) -16 = 0
(x-4)² + (y+2)² + z² = 16
(x-4)² + (y-(-2))² + (z-0)² = 4²
thus we have a=4 , b= -2 , c= 0 and R=4
