Please answer the question attached in the image if you can use ms paint to draw arrows that will be appreciated.

my brother and i walk the same route every day. my beother takes 40minutes to get to school and i take 30minutes to get to schoo

Goryan [66]

In 1 minute, I walk = 1/30

In 1 minute, My brother walk = 1/40

In T minutes, I walk = T*1/30

My brother walk 8 minute before = T + 8

In 1 minute, My brother walk = (T + 8)*1/40

When these two distances are same, then I will catch him.

T*(1/30) = (T + 8)*(1/40)

30*(T + 8) = 40*T

30*T + 240 = 40*T

240 = 10*T

T = 24 minutes

hence, I will catch him in 24 minutes.

Take 5 instead of 8.

My brother walk 5 minute before = T + 5

In 1 minute, My brother walk = (T + 5)*1/40

When these two distances are same, then I will catch him.

T*(1/30) = (T + 5)*(1/40)

30*(T + 5) = 40*T

30*T + 150 = 40*T

150 = 10*T

T = 15 minutes

Hence, I will catch him in 15 minutes.

6 0

3 years ago

Explain what the absolute value tells about -18°C.

butalik [34]

All you need to do is convert this to Kelvin.
Add 273.15 to Celcius to find Kelvin.
255.15 kelvin

7 0

3 years ago

Read 2 more answers

Aye plz help. Im abt to die. Find the perimiter of the shape below.

Law Incorporation [45]

Answer:

40

Step-by-step explanation:

Add all the sides together which is 40

4 0

3 years ago

If A=(0,0) and B=(8,2), what is the length of AB

NeX [460]

Answer:

$\boxed{\sf Distance_{AB}= 8.24 \ units }$

Step-by-step explanation:

Here two points are given to us and we need to find the distance between the two points . The given points are , A(0,0) and B(8,2) . The distance between the two points can be found out using the Distance Formula , which is ,

Distance Formula:-

$\sf\implies \green{ Distance =\sqrt{ (x_2-x_1)^2+(y_2-y_1)^2}}$

Therefore on substituting the respective values ,we can find the Distance as ,

$\sf\longrightarrow Distance = \sqrt{ ( 0 - 8)^2 + (0-2)^2}$

Simplify the brackets ,

$\sf\longrightarrow Distance =\sqrt{ (-8)^2+(-2)^2}$

Square the numbers inside the squareroot ,

$\sf\longrightarrow Distance =\sqrt{ 64 + 4}$

Add the numbers inside the squareroot ,

$\sf\longrightarrow Distance = \sqrt{68}$

Find the value of squareroot,

$\sf\longrightarrow \boxed{\blue{\sf Distance = 8.24 \ units }}$

Hence the distance between the two points is 8.24 units .

3 0

3 years ago

Which of the following could be the lengths of the sides for a triangle that is similar to the triangle shown?

artcher [175]

A,,,,they are multiples of the lengths indicated

6 0

3 years ago