In 1 minute, I walk = 1/30
In 1 minute, My brother walk = 1/40
In T minutes, I walk = T*1/30
My brother walk 8 minute before = T + 8
In 1 minute, My brother walk = (T + 8)*1/40
When these two distances are same, then I will catch him.
T*(1/30) = (T + 8)*(1/40)
30*(T + 8) = 40*T
30*T + 240 = 40*T
240 = 10*T
T = 24 minutes
hence, I will catch him in 24 minutes.
Take 5 instead of 8.
My brother walk 5 minute before = T + 5
In 1 minute, My brother walk = (T + 5)*1/40
When these two distances are same, then I will catch him.
T*(1/30) = (T + 5)*(1/40)
30*(T + 5) = 40*T
30*T + 150 = 40*T
150 = 10*T
T = 15 minutes
Hence, I will catch him in 15 minutes.
All you need to do is convert this to Kelvin.
Add 273.15 to Celcius to find Kelvin.
255.15 kelvin
Answer:
40
Step-by-step explanation:
Add all the sides together which is 40
Answer:

Step-by-step explanation:
Here two points are given to us and we need to find the distance between the two points . The given points are , <u>A(</u><u>0</u><u>,</u><u>0</u><u>)</u><u> </u>and <u>B(</u><u>8</u><u>,</u><u>2</u><u>)</u> . The distance between the two points can be found out using the<u> </u><u>Distance</u><u> Formula</u><u> </u>, which is ,
<em>Distance Formula:- </em>
Therefore on substituting the respective values ,we can find the Distance as ,
<u>Simpl</u><u>i</u><u>fy </u><u>the </u><u>brackets</u><u> </u><u>,</u>
Square the numbers inside the squareroot ,

Add the numbers inside the squareroot ,
Find the value of squareroot,
<u>Hence</u><u> the</u><u> </u><u>distance</u><u> between</u><u> the</u><u> two</u><u> points</u><u> </u><u>is</u><u> </u><u>8</u><u>.</u><u>2</u><u>4</u><u> </u><u>units </u><u>.</u>
A,,,,they are multiples of the lengths indicated