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aleksklad [387]
3 years ago
14

Please answer the question attached in the image if you can use ms paint to draw arrows that will be appreciated.

Mathematics
1 answer:
yawa3891 [41]3 years ago
7 0
2 1 1/2 3 3 3/4 your welcome
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my brother and i walk the same route every day. my beother takes 40minutes to get to school and i take 30minutes to get to schoo
Goryan [66]

In 1 minute, I walk = 1/30

In 1 minute, My brother walk = 1/40

In T minutes, I walk = T*1/30

My brother walk 8 minute before = T + 8

In 1 minute, My brother walk = (T + 8)*1/40

When these two distances are same, then I will catch him.

T*(1/30) = (T + 8)*(1/40)

30*(T + 8) = 40*T

30*T + 240 = 40*T

240 = 10*T

T = 24 minutes

hence, I will catch him in 24 minutes.

Take 5 instead of 8.

My brother walk 5 minute before = T + 5

In 1 minute, My brother walk = (T + 5)*1/40

When these two distances are same, then I will catch him.

T*(1/30) = (T + 5)*(1/40)

30*(T + 5) = 40*T

30*T + 150 = 40*T

150 = 10*T

T = 15 minutes

Hence, I will catch him in 15 minutes.


6 0
3 years ago
Explain what the absolute value tells about -18°C.
butalik [34]
All you need to do is convert this to Kelvin.
Add 273.15 to Celcius to find Kelvin. 
255.15 kelvin
7 0
3 years ago
Read 2 more answers
Aye plz help. Im abt to die. Find the perimiter of the shape below.
Law Incorporation [45]

Answer:

40

Step-by-step explanation:

Add all the sides together which is 40

4 0
3 years ago
If A=(0,0) and B=(8,2), what is the length of AB
NeX [460]

Answer:

\boxed{\sf Distance_{AB}= 8.24 \ units }

Step-by-step explanation:

Here two points are given to us and we need to find the distance between the two points . The given points are , <u>A(</u><u>0</u><u>,</u><u>0</u><u>)</u><u> </u>and <u>B(</u><u>8</u><u>,</u><u>2</u><u>)</u> . The distance between the two points can be found out using the<u> </u><u>Distance</u><u> Formula</u><u> </u>, which is ,

<em>Distance Formula:- </em>

\sf\implies \green{ Distance =\sqrt{ (x_2-x_1)^2+(y_2-y_1)^2}}

Therefore on substituting the respective values ,we can find the Distance as ,

\sf\longrightarrow Distance = \sqrt{ ( 0 - 8)^2 + (0-2)^2}

<u>Simpl</u><u>i</u><u>fy </u><u>the </u><u>brackets</u><u> </u><u>,</u>

\sf\longrightarrow Distance =\sqrt{ (-8)^2+(-2)^2}

Square the numbers inside the squareroot ,

\sf\longrightarrow Distance =\sqrt{ 64 + 4}

Add the numbers inside the squareroot ,

\sf\longrightarrow Distance = \sqrt{68}

Find the value of squareroot,

\sf\longrightarrow \boxed{\blue{\sf Distance = 8.24 \ units }}

<u>Hence</u><u> the</u><u> </u><u>distance</u><u> between</u><u> the</u><u> two</u><u> points</u><u> </u><u>is</u><u> </u><u>8</u><u>.</u><u>2</u><u>4</u><u> </u><u>units </u><u>.</u>

3 0
3 years ago
Which of the following could be the lengths of the sides for a triangle that is similar to the triangle shown?
artcher [175]
A,,,,they are multiples of the lengths indicated
6 0
3 years ago
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