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DanielleElmas [232]
2 years ago
8

ANYONE PLEASE HELP ME WITH MY MATH HOMEWORK I REALLY NEED THE ANSWER RIGHT NOW BECAUSE I HAVE TO PASS THIS LATER I DON’T HAVE MU

CH TIME LEFT I HOPE Y’ALL CAN HELP ME:(I’LL MARK BRAINLIEST FOR THOSE WHO CAN ANSWE IT CORRECTLY!
PS:PLEASE DON’T WASTE MY POINTS I’M WORKING HARD FOR THIS POINTS:(

Mathematics
1 answer:
sineoko [7]2 years ago
3 0

Answer:

Step-by-step explanation:

sorry for the photo quality but i dont hv aphone and use a laptop instead

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Which number line represents the solution to the inequality –4w + 7 < 75 ?
timama [110]

Answer:

w > − 17

Step-by-step explanation:

6 0
2 years ago
Write an inequality to match each description. Use n for the variable.
mel-nik [20]

{\huge {\mathfrak {Answer :-}}}

Let, the length be l and breadth be b.

So, 2(l + b) = 26

Or, l + b = 13

Or, l = 13 - b

So, we may write like this,

Area = l * b

Or, l * b > 30

Or, l (13 - l) > 30

Or, 13l - l^2 > 30

Or, l^2 - 13l + 30 > 0

Or, l^2 - 3l - 10l + 30 > 0

Or, l(l - 3) - 10(l - 3) > 0

Or, (l - 3)(l - 7) > 0

Or, l - 7 > 0

Or, l > 7.

Now, putting the value of l,

We get, l * b > 30

Or, 7 * b > 30

Or, b > 30/7

➡️ Therefore, we get,

Length > 7

Breadth > 30/7

That's it..

6 0
3 years ago
PLEASE NEEED HEELPP
krok68 [10]
There are many systems of equation that will satisfy the requirement for Part A.
an example is y≤(1/4)x-3 and y≥(-1/2)x-6
y≥(-1/2)x-6 goes through the point (0,-6) and (-2, -5), the shaded area is above the line. all the points fall in the shaded area, but
y≤(1/4)x-3 goes through the points (0,-3) and (4,-2), the shaded area is below the line, only A and E are in the shaded area. 
only A and E satisfy both inequality, in the overlapping shaded area.

 
Part B. to verify, put the coordinates of A (-3,-4) and E(5,-4) in both inequalities to see if they will make the inequalities true. 
 for y≤(1/4)x-3: -4≤(1/4)(-3)-3
-4≤-3&3/4 This is valid.
For y≥(-1/2)x-6: -4≥(-1/2)(-3)-6
-4≥-4&1/3 this is valid as well. So Yes, A satisfies both inequalities. 
Do the same for point E (5,-4)

Part C: the line y<-2x+4 is a dotted line going through (0,4) and (-2,0)
the shaded area is below the line
farms A, B, and D are in this shaded area. 
8 0
2 years ago
Plz help me I don't know how to do this!!!!
m_a_m_a [10]

Answer:

x = 25

Step-by-step explanation:

Since it is an equilateral triangle it means that all the sides are 50. Each side is equal so, if you divide 150 by 3 you get 50. (and since perimeter is the adding of each side)

Now you want to try to figure out what the altitude is of the triangle so you divide it in half. Making the bottom side length now 25 because half of 50 is 25. You now have to use Pythagoreans theorem to figure out the altitude:

c^2 - a^2 = b^2

50^2 - 25^2 = b^2

2500 - 625 = b^2

1875 = b^2

√1875 = b

43.30127019

now you put that into the expression: x√3:

x√3 = 43.30127019

x = (43.30127019) ÷ (√3)

x = 25

Hope this helped!

8 0
2 years ago
A study of long-distance phone calls made from General Electric's corporate headquarters in Fairfield, Connecticut, revealed the
Jet001 [13]

Answer:

a) 0.4332 = 43.32% of the calls last between 3.6 and 4.2 minutes

b) 0.0668 = 6.68% of the calls last more than 4.2 minutes

c) 0.0666 = 6.66% of the calls last between 4.2 and 5 minutes

d) 0.9330 = 93.30% of the calls last between 3 and 5 minutes

e) They last at least 4.3 minutes

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 3.6, \sigma = 0.4

(a) What fraction of the calls last between 3.6 and 4.2 minutes?

This is the pvalue of Z when X = 4.2 subtracted by the pvalue of Z when X = 3.6.

X = 4.2

Z = \frac{X - \mu}{\sigma}

Z = \frac{4.2 - 3.6}{0.4}

Z = 1.5

Z = 1.5 has a pvalue of 0.9332

X = 3.6

Z = \frac{X - \mu}{\sigma}

Z = \frac{3.6 - 3.6}{0.4}

Z = 0

Z = 0 has a pvalue of 0.5

0.9332 - 0.5 = 0.4332

0.4332 = 43.32% of the calls last between 3.6 and 4.2 minutes

(b) What fraction of the calls last more than 4.2 minutes?

This is 1 subtracted by the pvalue of Z when X = 4.2. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{4.2 - 3.6}{0.4}

Z = 1.5

Z = 1.5 has a pvalue of 0.9332

1 - 0.9332 = 0.0668

0.0668 = 6.68% of the calls last more than 4.2 minutes

(c) What fraction of the calls last between 4.2 and 5 minutes?

This is the pvalue of Z when X = 5 subtracted by the pvalue of Z when X = 4.2. So

X = 5

Z = \frac{X - \mu}{\sigma}

Z = \frac{5 - 3.6}{0.4}

Z = 3.5

Z = 3.5 has a pvalue of 0.9998

X = 4.2

Z = \frac{X - \mu}{\sigma}

Z = \frac{4.2 - 3.6}{0.4}

Z = 1.5

Z = 1.5 has a pvalue of 0.9332

0.9998 - 0.9332 = 0.0666

0.0666 = 6.66% of the calls last between 4.2 and 5 minutes

(d) What fraction of the calls last between 3 and 5 minutes?

This is the pvalue of Z when X = 5 subtracted by the pvalue of Z when X = 3.

X = 5

Z = \frac{X - \mu}{\sigma}

Z = \frac{5 - 3.6}{0.4}

Z = 3.5

Z = 3.5 has a pvalue of 0.9998

X = 3

Z = \frac{X - \mu}{\sigma}

Z = \frac{3 - 3.6}{0.4}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.9998 - 0.0668 = 0.9330

0.9330 = 93.30% of the calls last between 3 and 5 minutes

(e) As part of her report to the president, the director of communications would like to report the length of the longest (in duration) 4% of the calls. What is this time?

At least X minutes

X is the 100-4 = 96th percentile, which is found when Z has a pvalue of 0.96. So X when Z = 1.75.

Z = \frac{X - \mu}{\sigma}

1.75 = \frac{X - 3.6}{0.4}

X - 3.6 = 0.4*1.75

X = 4.3

They last at least 4.3 minutes

7 0
2 years ago
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