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TiliK225 [7]
4 years ago
13

In a large backyard, there are 4 times as many shrubs as trees. Altogether, there are 40 trees and shrubs. How many trees are in

the yard? How many shrubs?
Mathematics
2 answers:
Rzqust [24]4 years ago
8 0
Ten trees because Ten times Four is Forty. 
Nonamiya [84]4 years ago
7 0

Answer:

Please mark me brainliest and I hope this helped!

Trees: 8

Shrubs: 32

Step-by-step explanation:

If there are 4 times as many shurbs as trees, then in total, we should split it into 5 parts. So we should divide 40 by 5. That gives us 8, so there are 8 trees. Shrubs is 4 times as much, so there are 8 times 4 shrubs which is 32 shrubs.

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An archaeological site is to be made accessible for viewing by the public. To do this, archaeologists built two straight paths f
Jobisdone [24]

Answer:

387 km

Step-by-step explanation:

The length of AC, b can be obtained using the cosine rule ; using the cosine relation:

b² = a² + c² - 2ac CosB

b² = 250² + 185² - 2(250*185) Cos125

b² = 62500 + 34225 - 92500 * −0.573576

b² = 96725 + 53055.820

b² = 149780.82

b = sqrt(149780.82)

b = 387.01527

b = 387 km (nearest whole number)

5 0
3 years ago
HELP
stiv31 [10]
The Answer Is No Solution!
4 0
3 years ago
Find a polynomial f(x) of degree 4 that has the following zeros. 7, −3, 0, −2
HACTEHA [7]

Answer:

x^4 - 2x^3 - 29x^2 - 42x

Step-by-step explanation:

Equal all the zeros to x then move them over.

x=7,x=-3,x=0,x=-2

x-7,x+3,x+0,x+2

Then multiply each factor

(x-7)(x+3)(x)(x+2)

x^4 - 2x^3 - 29x^2 - 42x

7 0
3 years ago
Adult tickets to a play cost $22 tickets for kids cost $15. Tickets for a group of 11 cost a total of $228. How many children an
Zina [86]

Answer:Number of children = 2 and number of adults = 9 attended the play

Step-by-step explanation:

Step 1

Let the  number  of children be represented as  x

and the number of adults in the group  be represented as  as y

such that the total number of the group that went to the play

= x+y=11--- equation 1

And the total cost paid for the play will be expressed as

15x+  22y= 228------ equation 2

Step 2-- Solving

x+y=11--- equation 1

15x+  22y= 228------ equation 2

B y elimination method, multiply equation 1 by 15 to give equation 3  and then subtract from equation 2

15x+  22y= 228------ equation 2

15x+15Y= 165----- equation 3

7y=63

y= 63/7= 9

y= adults = 9

therefore x = number of children will be

x+y=11

x+ 9=11

x= 11-9= 2

In the group that attended the play,  Number of children = 2 and number of adults = 9

8 0
3 years ago
The length of a rectangle is 1 inch less than twice the width. the area is 21 inches^2 what is the length?
ale4655 [162]
Hi.

Formula for area: A = 2l + 2w, where l is the length and w is the width.

Given information:
• l = 2w - 1
• A = 21 in^2

We can plug in our values accordingly and solve for w.

A = 2l + 2w
21 = 2(2w - 1) + 2w
21 = 4w - 2 + 2w
23 = 6w - 2
23 = 6w
3.83 = w

Plug 3.83 for w into 2w - 1 to find length.

2(3.83) - 1
7.66 - 1
6.66

Finally, check your work by plugging your values into the original equation.

21 = 2(6.66) + 2(3.83)
21 = 13.32 + 7.66
21 = 20.98

Answer:
The length is approximately 6.66 inches.
4 0
3 years ago
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