Answer:
r = -4
Step-by-step explanation:
If M is the midpoint of DE, that would mean that the distance from M to D and M to E would be the same.
This creates the equation 1-8r=13-5r.
Now it's just simple algebra.
You add 8r to both sides, creating 1=13+3r. Then, you subtract 13 from both sides, getting 3r=-12. Dividing both sides by 3 and solving for r, you get r=-4.
Checking our answer, you see that 1-8(-4)=1-(-32)=1+32=33, and 13-5(-4)=13-(-20)=13+20=33.
I think you meant to have more of a problem stated.
Basically, you use the Law of Sines when you have 2 angles but the length of only one side.
The formula for this law is
a / sine(A) = b / sine(B) = c / sine(C)
Answer:
B
Step-by-step explanation:
For a polynomial , the behaviour as x gets large is determined by the term of greatest degree,
f(x) = - 2
- x³ + 3
Is of even degree with a negative leading coefficient , then
f(x) → - ∞ as x → + ∞ and f(x) → - ∞ as x → - ∞
Answer:
Step-by-step explanation:
Picture 1
In right triangle ABC,
Side AB is the opposite side of angle C.
Picture 2
In triangle MKL,
tan(∠M) = 
= 
= 
Option (1) is the answer.
Picture 3
In ΔXYZ,
sin(∠Z) = 
= 
For the length of XY we will apply Pythagoras theorem in ΔXYZ,
XZ² = XY² + YZ²
XY² = XZ² - YZ²
= (40)² - (32)²
XY = √576
= 24
sin(Z) =
sin(Z) =
Picture 4
In right triangle DEF,
Cos(D) = 
= 
= 
= 
Picture 5
In ΔABC,
tan(63°) = 
tan(63°) = 
AB = 
AB = 
AB = 4.0762 ≈ 4 m
Option (3) will be the answer.