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Nimfa-mama [501]
4 years ago
13

What is the greatest common factor of 45 and 60

Mathematics
2 answers:
Setler [38]4 years ago
8 0
It is 105 because 60+45=105
natali 33 [55]4 years ago
7 0
15 is the greatest common factor.
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Lostsunrise [7]

Answer:

b. mark plsssssss pls pls pls

7 0
3 years ago
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HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP(25 points)
miskamm [114]

Answer: I hope it helps :)

  • x=6 , y=6√3
  • x =23√3 , y=23
  • u =12 , v= 6
  • a =18√2 , b =18
  • x = 13 , y= 13

Step-by-step explanation:

1.

Hypotenuse =x\\Opposite =y \\Adjacent =6\\\alpha = 6\\Let's\: find\: the \:hypotenuse\: first\\Using SOHCAHTOA\\Cos \alpha = \frac{adj}{hyp} \\Cos 60 = \frac{6}{x} \\\frac{1}{2} =\frac{6}{x} \\Cross\:Multiply\\x = 12\\Let's\: find\: y\\Hyp^2=opp^2+adj^2\\12^2=y^2+6^2\\144=y^2+36\\144-36=y^2\\108=y^2\\\sqrt{108} =\sqrt{y^2} \\y=6\sqrt{3}

2.

Opposite =x\\Hypotenuse = 46\\Adjacent =y \\\alpha =60\\Using \: SOHCAHTOA\\Sin \alpha =\frac{opp}{adj} \\Sin 60=\frac{x}{46}\\\\\frac{\sqrt{3} }{2} =\frac{x}{46}  \\2x=46\sqrt{3} \\x = \frac{46\sqrt{3} }{2} \\x =23\sqrt{3} \\\\Hyp^2=opp^2+adj^2\\46^2=(23\sqrt{3} )^2+y^2\\2116=1587+y^2\\2116-1587=y^2\\529=y^2\\\sqrt{529} =\sqrt{y^2} \\y = 23

3.

Hypotenuse = u\\Opposite =6\sqrt{3} \\Adjacent = v\\\alpha =60\\Sin\: 60 = \frac{6\sqrt{3} }{u} \\\frac{\sqrt{3} }{2} =\frac{6\sqrt{3} }{u} \\12\sqrt{3} =u\sqrt{3} \\\\\frac{12\sqrt{3} }{\sqrt{3} } =\frac{u\sqrt{3} }{\sqrt{3} } \\u = 12\\Hyp^2=opp^2+adj^2\\12^2= (6\sqrt{3} )^2+v^2\\144=108+v^2\\144-108=v^2\\36 = v^2\\\sqrt{36} =\sqrt{v^2} \\\\v =6

4.

Hypotenuse = a\\Opposite =18 \\Adjacent = b\\\alpha =45\\Tan \alpha = opp/adj\\Tan \:45 =18/b\\1=\frac{18}{b}\\ b = 18\\\\Hyp^2=Opp^2+Adj^2\\a^2 = 18^2+18^2\\a^2=324+324\\a^2=648\\\sqrt{hyp^2} =\sqrt{648}\\ \\a =18\sqrt{2}

5.

Hypotenuse = 13\sqrt{2}\\ Opposite =x\\Adjacent = y\\\alpha =45\\Sin\:\alpha = opp/hyp\\Sin 45=x/13\sqrt{2}\\ \\\frac{\sqrt{2} }{2} =\frac{x}{13\sqrt{2} } \\2x=26\\2x/2=26/2\\\\x = 13\\\\Hyp^2=opp^2+adj^2\\(13\sqrt{2})^2=13^2+y^2\\ 338=169+y^2\\338-169=y^2\\169=y^2\\\sqrt{169} =\sqrt{y^2} \\13 = y

7 0
3 years ago
(Due Now!! HELP; I know how to do this I just don't have time)
qaws [65]

Answer:

It is C.

Step-by-step explanation:

You divided 6.57 by 3

and 3 by 3

3 by 3 = 1

6.57 = 2.19

3 so for every 1 pound it costs $2.19

6 0
3 years ago
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How to find the y axis on a graph
forsale [732]
It’s the vertical axis (up and down)
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A certain electronics manufacturer found that the average cost C to produce x DVD/Blu- ray players can be found using the equati
lilavasa [31]

Answer:

<em>The minimum average cost is $2.80 when 163 players are built</em>

Step-by-step explanation:

<u>Average Cost Function</u>

<em>We'll assume the given function as the total cost to produce x players, and NOT the average cost since that is a different definition, as shown below.</em>

The cost C to produce x DVD/Blu- ray players is given by the equation

C=0.03x^2-7x+800

The Average Cost function  is defined as

\displaystyle\bar  C=\frac{C}{x}

\displaystyle\bar  C=\frac{0.03x^2-7x+800}{x}

\displaystyle\bar  C=0.03x-7+\frac{800}{x}

To find the extreme value of the average cost, we must take the first derivative of the function

\displaystyle\bar  C'=0.03-\frac{800}{x^2}

Equating to 0

\displaystyle 0.03-\frac{800}{x^2}=0

Solving for x

\displaystyle x=\sqrt{\frac{800}{0.03}}

x=163

The second derivative is

\displaystyle\bar  C''=\frac{1600}{x^3}

For x=163 the second derivative is positive, thus x=163 is a minimum value. Let's compute the minimum average cost

\displaystyle\bar  C(163)=0.03\cdot 163-7+\frac{800}{163}

\displaystyle\bar  C(163)=2.80

The minimum average cost is $2.80

5 0
3 years ago
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