Answer:
hello your question is incomplete below is the missing parts
(a) A\ (A\B) = B\(B\A)
(b) A\ (BA) = B\(A\B)
answer : A\ (A\B) = B\(B\A) = always true
A\ (BA) = B\(A\B) = sometimes true and sometimes false
Step-by-step explanation:
(a) A\ (A\B) = B\(B\A). = ALWAYS TRUE
using de Morgan's law to prove this
A\ (A\B) = A\ ( A ∩ B^c )
= A ∩ ( A^C ∪ B )
= ( A ∩ A^C ) ∪ ( A ∩ B )
= Ф ∪ ( A ∩ B )
= ( A ∩ B )
ALSO : B\(B\A) = attached below is the remaining parts of the solution
B) A\ (BA) = B\(A\B) = Sometimes true and sometimes false
attached below is the prove using De Morgan's law
Answer:
21
Step-by-step explanation:
The average rate of change of function f(x) from x = a to x = b is
Here we have
a = -1
b = 2
f(a) = f(-1) = 1
f(b) = f(2) = 64
Answer:
Greatest = 699,999
Least = 600,900
Step-by-step explanation:
6 digit numbers
9 in the Hundred place
3 fewer hundred thousands than hundred
9 - 3 = 6
Hundred thousand = 600,000
Hence, greatest 6 digit number
Hth__TTh__Th__H__T__U
6____9____9___9__9__9
600,000 + 90,000 + 9,000 + 900 + 90 + 9
= 699,999
Hence, least 6 digit number
Hth__TTh__Th__H__T__U
6____0____0___9__0__0
600,000 + 00000 + 0000 + 900 + 00 + 0
= 600,900
Answer:
Yes
Step-by-step explanation:
Answer:
2 = 12
Step-by-step explanation:
This equation is considered false, but can be evaluated into adding -6 and 8.
That gives you 2 = 12.
