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2 years ago

can anyone help?????? Can y’all write it detailed or like step by step explaining cause i have to write it down ..

Mathematics

2 answers:

inysia [295]2 years ago

7 0

Answer:

x = 5

Step-by-step explanation:

Step 1: Distributive property

Using this property means when you have something like the equation on the right side ( 4 ( x + 3 ) ) you multiply both the values in the parentheses by the number outside:

4 ( x + 3 )

( 4 x X ) + ( 4 x 3 )

4x + 12

8x + 2 = 2x + 4x + 12

Step 2: combine like terms

Combining like terms is when you find like terms with the same variables and such and add them together:

8x + 2 = 12 + ( 2x + 4x )

8x + 2 = 12 + 6x

Step 3:Using inverse operations

This means that you need to get a variable one one side and a constant on the other:

8x + 2 ( -2 ) = 12 ( -2 ) + 6x

8x = 10 + 6x

8x ( -6x ) = 10 + 6x ( -6x )

2x = 10

Step 4: solve for the variable

The last thing you need to do is divide both sides by the constant with the variable ( 2x ) to get x by itself:

2x ( /2 ) = 10 ( /2 )

x = 5

aliina [53]2 years ago

3 0

Answer:

x=5

Step-by-step explanation:

Step 1:Using the distributive property on the right side of the equation

8x+2=2x+4(x+3)

8x+2=2x+4x+12

Step2:Combining the like terms on the right side if the equation (Since there are no like terms on the left side) :

8x+2=6x+12

Step 3: Using the inverse operations to get the variables on the left side and the constants on the right side of the equation :

8x-6x=12-2

Step4: Using inverse operation to solve for the variable of interest which is 'x':

2x=10 (Dividing both sides by two sides by 2)

x=5

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Select all the expressions that are equivalent to (2)^n+³

eimsori [14]

Answer:

The expressions which equivalent to $(2)^{n+3}$ are:

$4(2)^{n+1}$ ⇒ B

$8(2)^{n}$ ⇒ C

Step-by-step explanation:

Let us revise some rules of exponent

$a^{m}$ × $a^{m}$ = $a^{m+n}$
$(a^{m})^{n}$ = $a^{m*n}$

Now let us find the equivalent expressions of $(2)^{n+3}$

∵ 4 = 2 × 2

∴ 4 = $2^{2}$

∴ $(4)^{n+2}$ = $(2^{2})^{n+2}$

- By using the second rule above multiply 2 and (n + 2)

∵ 2(n + 2) = 2n + 4

∴ $(4)^{n+2}$ = $(2)^{2n+4}$

∵ 4 = 2 × 2

∴ 4 = 2²

∴ $4(2)^{n+1}$ = 2² × $(2)^{n+1}$

- By using the first rule rule add the exponents of 2

∵ 2 + n + 1 = n + 3

∴ $4(2)^{n+1}$ = $(2)^{n+3}$

∵ 8 = 2 × 2 × 2

∴ 8 = 2³

∴ $8(2)^{n}$ = 2³ × $(2)^{n}$

- By using the first rule rule add the exponents of 2

∵ 3 + n = n + 3

∴ $8(2)^{n}$ = $(2)^{n+3}$

∵ 16 = 2 × 2 × 2 × 2

∴ 16 = $2^{4}$

∴ $16(2)^{n}$ = $2^{4}$ × $(2)^{n}$

- By using the first rule rule add the exponents of 2

∵ 4 + n = n + 4

∴ $16(2)^{n}$ = $(2)^{n+4}$

$(2)^{2n+3}$ is in its simplest form

The expressions which equivalent to $(2)^{n+3}$ are:

$4(2)^{n+1}$ ⇒ B

$8(2)^{n}$ ⇒ C

3 0

3 years ago

X²=14x-45 step by step please

dolphi86 [110]

Answer:

X=9 and X=5

Step-by-step explanation:

So you want to get one side to equal zero so you can factor and find x. I recommend subtracting 14x and adding 45 to both sides so you don't have to deal with a negative quadratic.

X^2 - 14X +45 = 0

Now you can factor. Your looking for two factors that equal 45 and add to -14

All factors of 45:

1 and 45, 3 and 15, 5 and 9, -1 and -45,

-3 and -15, -5 and -9

So out of those combinations -5 and -9 both multiply to 45 and add up to -14 so these are our common factors

(X-5)(X-9)=0

X-5=0 add 5 to both sides X=5

X-9=0 add 9 to both sides X=9

5 0

2 years ago

For function of g,g(0)=1 and g(1)=5 assuming g is a linear function what is g(3)<br>