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3 years ago

Help me please! This is urgent.

Mathematics

2 answers:

DochEvi [55]3 years ago

7 0

Answer: W

Step-by-step explanation:

pychu [463]3 years ago

3 0

Answer:

I think W or Z but not really sure so

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The perimeter of the patio is 32m. the garden itself is a square shape. what is the total area of the garden and the patio?

melamori03 [73]

64 32 divided by 4 is 8 8 tmes 8 is 64

4 0

3 years ago

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Help pls don not under stand

m_a_m_a [10]

The expected value of health care without insurance is $437.25.

The expected value of health care with insurance is $1,636.40.

<h3>What are the expected values?</h3>

The expected values can be determined by multiplying the respective probabilities by its associated costs.

The expected value of health care without insurance = (1 x 0) + (0.32 x 1050) + (0.45 x $225) = $437.25.

The expected value of health care with insurance = (1 x 1580) + (0.32 x 75) + (0.45 x $72) = $1,636.40.

To learn more about multiplication, please check: brainly.com/question/13814687

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2 years ago

Please help I'll give brainiest

Komok [63]

For the first is 3864
The second is 1320
A=3.14(which is pie) x 20.5^2
A=420x pie
A=1320
For the third is 2544
3864-1320=2544
Sorry if this is wrong too.

8 0

3 years ago

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Two trains leave the station at the same time, one heading east and the other west. The eastbound train travels at 115 miles per

xz_007 [3.2K]

X= 115x95 this is because when you solve it will give you your answer

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3 years ago

Do bonds reduce the overall risk of an investment portfolio? Let x be a random variable representing annual percent return for t

rjkz [21]

Answer:

COV (all stocks) = 0.55

COV (stocks and bonds) = 0.82

Step-by-step explanation:

Coefficient of Variation is used to measure variability.

It is defined as the ration of standard deviation and the mean.

It can be used to compare variability of two population or two samples.

Formula:

$\text{Coefficient of Variation} = \displaystyle\frac{\text{Standard Deviation}}{\text{Mean}}$

$\text{Standard Deviation} = \sqrt{\displaystyle\frac{\sum (x_i -\bar{x})^2}{n-1}}$

where $x_i$ are data points, $\bar{x}$ is the mean and n is the number of observations.

$Mean = \displaystyle\frac{\text{Sum of all observations}}{\text{Total number of observation}}$

x: 14, 0, 39, 25, 32, 27, 28, 14, 14, 15

$Mean = \frac{208}{10} = 20.8$

$Standard~Deviation = \sqrt{\frac{1169.6}{9} } = 11.39$

$Coefficient~of~Variation = \frac{11.39}{20.8} = 0.55$

y = 6, 2, 29, 17, 26, 17, 17, 2, 3, 5

$Mean = \frac{124}{10} = 12.4$

$Standard~Deviation = \sqrt{\frac{924.4}{9} } = 10.13$

$Coefficient~of~Variation = \frac{10.13}{12.4} = 0.82%$

Since coefficient of variation of x is less compared to y, thus it could be said bonds does not reduce overall risk of an investment portfolio.

6 0

3 years ago