To solve for this, we need to find for the value of x
when the 1st derivative of the equation is equal to zero (or at the
extrema point).
So what we have to do first is to derive the given
equation:
f (x) = x^2 + 4 x – 31
Taking the first derivative f’ (x):
f’ (x) = 2 x + 4
Setting f’ (x) = 0 and find for x:
2 x + 4 = 0
x = - 2
Therefore the value of a is:
a = f (-2)
a = (-2)^2 + 4 (-2) – 31
a = 4 – 8 – 31
a = - 35
Loge 70.81 = a
Log to the base e is also written as ln
ln 70.81 = a
Answer:
If you draw a diagonal across the parallelogram from one vertex to the opposite vertex, you divide the parallelogram into two congruent triangles. Each triangle thus has 1/2 of the area of the parallelogram.
Answer:
Step-by-step explanation:
Isolate the term of x from one side of the equation.
<h3>x-5≤10</h3>
<u>First, add by 5 from both sides.</u>
<u>Solve.</u>
<u>Add the numbers from left to right.</u>
- <u>Therefore, the solution is x≤15, which is our answer.</u>
I hope this helps you! Let me know if my answer is wrong or not.
