Answer:
(1,1)(3,-2)
Step-by-step explanation:
a hope this answer helping you
Answer:
- 33 1/3 liters of 30%
- 16 2/3 liters of 45%
Step-by-step explanation:
Let x represent the liters of 45% solution needed. Then the amount of HCl in the mix is ...
0.45x +0.30(50 -x) = 0.35(50)
0.15x = 0.05(50) . . . . . simplify, subtract 0.30(50)
x = (0.05/0.15)(50) = 50/3 = 16 2/3 . . . liters of 45% HCl
33 1/3 liters of 30% and 16 2/3 liters of 45% HCl are needed.
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<em>Comment on the solution</em>
You may notice that the general solution to a mixture problem of this sort is that the fraction of the mix that is the highest contributor is ...
(mix % - low %) / (high % - low %) = (.35 -.30) / (.45 -.30) = .05/.15 = 1/3
-5x+4y=11
substitute for x which is 5
(-5)(5)+4y=11
simplify :
4y-25=11
add 25 on both sides
4y-25=11
+25 +25
the 25 cancels out
so it would be 4y=36
and you divide both sides by 4
4/4 =36/4
which gives you (5,9)
x= 5 , y =9
One way:
585-320=265 (Rounding to the nearest 5)
590-320=270 (Rounding to the nearest 10)
600- 300= 300 (Rounding to the nearest 100)
Hope you found this helpful :)
B. Is the right answer
First you have to take the common elements then use an identity/formula to get the rest
x^3 - 3x^2 + x-3
x^2 (x-3) +1 (x-3)
(x^2 +1) (x-3)
(x-1)(x+1)(x-3) {using a^2-b^2 on x^2-1^2}
