How do you solve a quadratic function using x^2+bx+c?
1 answer:
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<span>[x + 2 - (5x + 5)] ² =
[x + 2 - 5x - 5]² =
[x - 5x + 2 - 5]² =
[-4x - 3]² =
(-4x)² - 2.(-4x).3 + (-3)² =
16x² + 24x + 9
Answer:
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[x + 2 - 5x - 5]² =
[x - 5x + 2 - 5]² =
[-4x - 3]² =
(-4x)² - 2.(-4x).3 + (-3)² =
16x² + 24x + 9
Answer:
</span>
</span>