3x^2 = 2(x + 4)
3x^2 = 2x + 8
3x^2 - 2x - 8 = 0
(3x + 4)(x - 2) = 0
3x + 4 = 0
3x = -4
x = -4/3
x - 2 = 0
x = 2
solution is : x = -4/3 or x = 2 <==
Substitute in x = 2:
y = 5(2) + 3
y = 10 + 3
y = 13
To find the measure of x, we can use Pythagoras' Theorem of c² - b² = a². In this case, c would be 26 (AB), and b would be 22 (AC), so you can plug in the numbers and write it as
26² - 22² = x²
676 - 484 = x²
192 = x²
√
x = 13.86 (2 d.p)
So your answer is x = 13.86, I hope this helps!
